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Aleks04 [339]
3 years ago
14

Need help w/math will vote brainliest!

Mathematics
1 answer:
Digiron [165]3 years ago
3 0

Answer:

43

Step-by-step explanation:

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Estimate the rate of change of the graphed function over the interval -4 <_ x <_ 0
dezoksy [38]

Answer:

  0.2071

Step-by-step explanation:

It looks like the graph is of the function ...

  y = √(x +8) -2

We know that (-4, 0) is one point on the graph. The other point of interest is at x=0, where y = √8 -2 ≈ 0.8284.

The average rate of change on the interval is then ...

  m = (0.8284 -0)/(0 -(-4)) = 0.2071

The average rate of change on the interval is about 0.2071.

_____

<em>Rougher estimate</em>

The graph goes through the points (-4, 0) and (1, 1), so has a slope of 1/5 = 0.2 on the interval [-4, 1]. We know the graph does not go through (0, 1), so the slope is not as high as 1/4 = 0.25. The curve is concave downward, so the average slope will be higher than 0.2, but we aren't sure how much higher.

A reasonable estimate of the rate of change on the interval is "a little more than 0.2, but less than 0.25."

4 0
3 years ago
Find the value of x and y.
allochka39001 [22]

Answer:

(5y+5) is not right sorry

Step-by-step explanation:

6 0
3 years ago
Just need the explain your answer part. Can anyone help seventh grade math please DESPRATE
Dima020 [189]

9514 1404 393

Answer:

  140, 35, 260/35, 7.43, 8

Step-by-step explanation:

The last section is just a summary of the preceding sections, a short description of the problem and how you worked it.

She sells the jackets for 140% of $25, or $35. 260/35 = 7.43 She can only sell a whole number of jackets, so she needs to sell 8.

8 0
3 years ago
PLEASE HELP I DONT HAVE MUCH TIME
vaieri [72.5K]

Answer: Choice A.   1/64

Work Shown:

f(x) = 4^x

f(-3) = 4^(-3)

f(-3) = 1/(4^3) ... see note below

f(-3) = 1/64

Note: I'm using the rule that a^(-b) = 1/(a^b)

4 0
3 years ago
Read 2 more answers
12+4(8x-1) please help
MakcuM [25]

Answer:

32x+8

Step-by-step explanation:

You’re welcome :)

6 0
3 years ago
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