The program is an illustration of loops; Loops are program statements used for repetition of operations
<h3>How to complete the code?</h3>
The complete question is added as an attachment
The code written in Python that completes the missing parameters in the question are:
def nested_sum(mylist):
total = 0
for other_list in mylist:
total += sum(other_list)
print(total)
t = [[1,2],[3],[4,5,6]]
nested_sum(t)
nested_sum( eval(input()))
Read more about loops at:
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Answer:
D
Explanation:
The other answer choices make no sense so it's D.
Answer: enable network encryption to prevent authorized computer from accessing the wireless network.
Explanation:
1.open the wireless security settings on your router’s configuration page.
2. select security method you wish to use.
3.Enter a passphrase needed to access the network whenever authorizes personnel want access to network.
Answer:
The correct answer is letter "A": Engage.
Explanation:
Social media has gained importance not only as an informative medium but as a means for marketing. The 4E framework states the four basic characteristics social media advertisement should fulfill. Those components are:
- Excite.<em> Provide customers attractive offers.</em>
- Educate.<em> Give consumers information about the product and the offering.</em>
- Experience.<em> Allow direct or indirect interaction with the good.</em>
- <u>Engage</u>.<em> Involve customers in activities related to the product that transcend the simple buying of the good.</em>
Answer:
def max_n(arr, n):
arr.sort()
i = len(arr)-n
return arr[i:]
Explanation:
Define a function called max_n that takes two parameters, an array and an integer
Sort the array
In order to get the last n largest values, we need to slice the array. To do that we need a starting point. Our starting point of slicing will be the "lentgh of the array - n". That means, if we start slicing from that index to the last in the sorted array, we will get the last n largest values.
Assume array is 10, 2, 444, 91 initially.
When we sort it, it becomes 2, 10, 91, 444
Now let's say we want last 2 largest values, our sliced array index should start from 2 and go until the end
i = 4 - 2 = 2 → arr[2:] will return us 91 and 444
