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V125BC [204]
3 years ago
9

Pls help I will mark you the brainliest

Computers and Technology
2 answers:
ehidna [41]3 years ago
6 0

Answer:

c

Explanation:

nekit [7.7K]3 years ago
6 0

Answer:

Functionality is more important

Explanation:

Because even if something looks nice dosent mean it will work properly. Take the game cyberpunk for example even though it looked nice it had a lot of bugs which made everything else irrelavant.

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The class at the top of exception class hierarchy is ..........................
Lynna [10]

Answer:

<u>B) Throwable</u>

Explanation:

Great question, it is always good to ask away and get rid of any doubts that you may be having.

There are a wide range of classes on the exception class hierarchy. All the way on the top is the Objects Class but since that is not an available answer we will move on to the next one. The next one is the <u>Throwable</u> class. therefore that is the answer.

**Exception is after Throwable , and Arithmetic Exception is at the bottom.... everything is a class so that is not a part of the hierarchy **

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

6 0
3 years ago
Ill give 100 points to whoever gives me the CORRECT answer. I keep getting syntax errors when I do the "add:" part. Can someone
Olin [163]

Answer:

sorry but there is not enough information to complete this

Explanation:

6 0
3 years ago
Read 2 more answers
Accenture is helping a large retailer transform their online sales and services. The Data Analyst audits the client’s customer j
Allushta [10]

Answer:

d. by increasing their customer knowledge and leveraging that information to improve customer experience

Explanation:

Consumers are at the heart of all businesses as they are the ones who our product are targeted. They purchase these goods and the company makes profit. Therefore, it is paramount for businesses to identify their target consumers in other to understand their preference and serve them accordingly. With data analytics, a consumers purchase history, likes and viewed products may be used to improve relationship between consumers and service providers. Once a consumer's preference is anlysed using data, then this is leveraged to improve the kind of service offered to such consumer leasing to better consumer experience.

4 0
3 years ago
In Java.Use a single for loop to output odd numbers, even numbers, and an arithmetic function of an odd and even number. Use the
rosijanka [135]

Answer:

<em>This program is written using java programming language</em>

<em>Difficult lines are explained using comments (See Attachment for Source file)</em>

<em>Program starts here</em>

import java.util.*;

import java.lang.Math;

public class oddeven{

public static void main(String [] args)

{

 double even,odd;//Declare variables even and odd as double

 //The next iteration prints odd numbers

 for(int i = 1;i<=173;i+=2)

 {

  odd = i;

  System.out.format("%.4f",odd);//Round to 4 decimal places and print

System.out.print("\t");

 }

 System.out.print('\n');//Start printing on a new line

 //The next iteration prints even numbers

 for(int i = 0;i<=173;i+=2)

 {

  even=i;

  System.out.format("%.4f",even);//Round to 4 decimal places and print

System.out.print("\t");

 }

 System.out.print('\n');//Start printing on a new line

 double  ssqrt;//Declare ssqrt to calculate the square root of sum of even and odd numbers

 for(int i = 0;i<=173;i+=2)

 {

  ssqrt = Math.sqrt(2*i+1);//Calculate square root here

  System.out.format("%.4f",ssqrt); //Round to 4 decimal places and print

System.out.print("\t");

 }

}

}

Explanation:

Libraries are imported into the program

import java.util.*;

import java.lang.Math;

The following line declares variables even and odd as double

double even,odd;

The following iteration is used to print odd numbers  with in the range of 0 to 173

for(int i = 1;i<=173;i+=2)  {

odd = i;

System.out.format("%.4f",odd); This particular line rounds up each odd numbers to 4 decimal places before printing them

System.out.print("\t"); This line prints a tab

}

The following code is used to start printing on a new line

System.out.print('\n');

The following iteration is used to print even numbers  with in the range of 0 to 173

for(int i = 0;i<=173;i+=2)

{

even=i;

System.out.format("%.4f",even); This particular line rounds up each even numbers to 4 decimal places before printing them

System.out.print("\t"); This line prints a tab

}

The following code is used to start printing on a new line

System.out.print('\n');

The next statement declares ssqrt as double to calculate the square root of the sum of even and odd numbers

double  ssqrt;

for(int i = 0;i<=173;i+=2)

{

ssqrt = Math.sqrt(2*i+1);This line calculates the square root of sum of even and odd numbers

System.out.format("%.4f",ssqrt); This particular line rounds up each even numbers to 4 decimal places before printing them

System.out.print("\t"); This line prints a tab

}

Download java
7 0
3 years ago
Which expression correctly determines that String s1 comes before String s2 in lexicographical order
Assoli18 [71]

Options :

A.) s1 < s2

B.) s1 <= s2

C.) s1.compareTo(s2) == −1

D.) s2.compareTo(s1) < 0

E.) s1.compareTo(s2) < 0

Answer: E.) s1.compareTo(s2) < 0

Explanation: Lexicographical ordering simply means the arrangement of strings based on the how the alphabets or letters of the strings appear. It could also be explained as the dictionary ordering principle of words based on the arrangement of the alphabets. In making lexicographical comparison between strings, the compareTo () method may be employed using the format below.

If first string = s1 ; second string = s2

To compare s1 with s2, the format is ;

s1.compareTo(s2) ;

If s1 comes first, that is, before s2, the method returns a negative value, that is a value less than 0 '< 0', which is the case in the question above.

If s2 comes first, that is, before s1, the method returns a positive value, that is a value greater than 0 '> 0'.

If both are s1 and s2 are the same, the output will be 0.

8 0
3 years ago
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