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3 years ago

CAN SOMEBODY PLEASE HELP ME I DONT UNDERSTAND THIS ILL FAILED! REWARD BRAINLIESTSS

Mathematics

2 answers:

bonufazy [111]3 years ago

5 0

Answer:the 3rd one

Step-by-step explanation:

Feliz [49]3 years ago

5 0

1. b

2. d

3. c

4. a

5. b

I'm very sorry if I am incorrect.

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Help me please ❤️<br> Thank you

anyanavicka [17]

Answer:

I think it would be finding the quantity in each group.

Step-by-step explanation:

Because there would be more than 1 group. there is only one group. so you are trying to find the number of hours each person in the group will get.

i think that is right sorry if not.

5 0

3 years ago

Read 2 more answers

Please help!!! Thanks!

Darina [25.2K]

8x+(4*30)=6(6+30)
8x+120=6x+180
2x=60
x=30 pounds of coffee

3 0

3 years ago

What is the sum of the first 6 terms of the series <br> -1+4-16+...

Romashka [77]

Answer:

819

Step-by-step explanation:

Givens

a = -1
r = - 4
n = 6

Formula

Sum = a(1 - r^n) / ( 1 - r)

Sum = -1(1 - (-4)^6 / (1 - -4)

Sum = -1 (1 - 4096) / 5

Sum = -1 (- 4095 ) / 5

Sum = 819

4 0

3 years ago

Yumiko solved |x|>5 by solving x>-5 and x<5. explain the error yumiko made

Whitepunk [10]

Answer:

switched signs around

Step-by-step explanation:

I believe that s/he switched the signs around so

|x|>5 is solved by x<-5 and x>5

but I'm not quite sure, sorry

3 0

2 years ago

You want to obtain a sample to estimate a population proportion. At this point in time, you have no reasonable estimate for the

Vesna [10]

Answer:

A sample size of at least 1,353,733 is required.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

98% confidence level

So $\alpha = 0.02$ , z is the value of Z that has a pvalue of $1 - \frac{0.02}{2} = 0.99$ , so $Z = 2.327$ .

You would like to be 98% confident that you esimate is within 0.1% of the true population proportion. How large of a sample size is required?

We need a sample size of at least n.

n is found when M = 0.001.

Since we don't have an estimate for the proportion, we use the worst case scenario, that is $\pi = 0.5$

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.001 = 2.327\sqrt{\frac{0.5*0.5}{n}}$

$0.001\sqrt{n} = 2.327*0.5$

$\sqrt{n} = \frac{2.327*0.5}{0.001}$

$(\sqrt{n})^{2} = (\frac{2.327*0.5}{0.001})^{2}$

$n = 1353732.25$

Rounding up

A sample size of at least 1,353,733 is required.

5 0

3 years ago