<span>√x^2+2x-10=√x+20
raising both members to the square
</span> x^2+2x-10=x+20
rewriting
x^2+x-30=0
factoring
(x+6)(x-5)=0
therefore the solutions are
<span> x = –6, x = 5
</span>the answer is
<span>B. x = –6, x = 5</span>
Answer:
The measure of ∠BDA is 30 Degrees.
Step-by-step explanation:
Lets construct a trapezium with the given data
If O is the point of intersection of the diagonals, ∆ AOD ~ ∆COB. Then
On substituting the given values
Also we know that AC = 6 . That is
AO + OC = 6 or OC = 6 - AO
substituting for CO and cross multiply
5·AO = (6-AO)·7
5AO = 42 - 7AO
12AO = 42
AO = = 3.5
All of the angles at E are right angles, so has the trigonometric ratio
= = 0.5 =
∠BDA = arcsin(1/2) = 30°
Answer:
y = 2x – 13
Step-by-step explanation:
Use Slope formula to get the slope
(y2-y1) / (x2-x1)
(-7--1) / (3-6)
(-6)/(-3)
2
Then plug-in the value of slope and any one coordinate in Point-Slope formula:
y- y1= m(x-x1)
y - -1 = 2( x - 6)
y + 1 = 2x - 12
y = 2x - 13
2. sqrt56x^2 = sqrt4*14*x^2 = 2x sqrt14 LETTER B
3. sqrt250h^4k^5 = sqrt 25*10*h^4*k^4*k = 5h^2k^2 sqrt10k LETTER C
4. sqrt15y * 3sqrt81y = sqrt15y * 27sqrt y = 27sqrt15y^2 LETTER C