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Anuta_ua [19.1K]
3 years ago
8

A circle has a center at A (4,5), Determine the radius of the circle given two end points of the circle are B (9,5) and C (-1,5)

Mathematics
1 answer:
Anna71 [15]3 years ago
4 0

ANSWER :

The center-radius form of the circle equation is in the format (x – h)2 + (y – k)2 = r2, with the center being at the point (h, k) and the radius being "r". This form of the equation is helpful, since you can easily find the center and the radius.

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Calculus: Help ASAP
Serggg [28]
\bf \displaystyle \int\limits_{-1}^{0}~(4x^6+2x)^3(12x^5+1)\cdot  dx\\\\
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u=4x^6+2x\implies \cfrac{du}{dx}=24x^5+2\implies \cfrac{du}{2(12x^5+1)}=dx\\\\
-------------------------------\\\\
\displaystyle \int\limits_{-1}^{0}~u^3\underline{(12x^5+1)}\cdot\cfrac{du}{2\underline{(12x^5+1)}}\implies \cfrac{1}{2}\int\limits_{-1}^{0}~u^3\cdot du\\\\
-------------------------------\\\\

\bf \textit{now, we'll change the bounds, using u(x)}
\\\\\\
u(-1)=4(-1)^6+2(-1)\implies u(-1)=2
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u(0)=4(0)^6+2()\implies u(0)=0\\\\
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\displaystyle \cfrac{1}{2}\int\limits_{2}^{0}~u^3\cdot du\implies \left. \cfrac{1}{2}\cdot \cfrac{u^4}{4}  \right]_{2}^{0}\implies \left. \cfrac{u^4}{8}  \right]_{2}^{0}\implies [0]-[2]\implies -2
5 0
3 years ago
Simplify (2/5÷3/8)÷(-3/5)
liberstina [14]

Answer:

\pink{ - 1 \frac{7}{9} }

Step-by-step explanation:

( \frac{2}{5}  \div  \frac{3}{8} ) \div ( -  \frac{3}{5} ) \\ (\frac{2}{5}  \times  \frac{8}{3} ) \times ( -  \frac{5}{3} ) \\  \frac{16}{15}  \times  -  \frac{5}{3}  \\ -   \frac{80}{45}

As the answer can be more simplified, divide both numerator and denominator by 5.

-  \frac{16}{9}  =   - 1 \frac{7}{9}

3 0
1 year ago
PLS HELP IM DESPARATE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
jeka57 [31]

Answer:

x=30°

2x=60°

Step-by-step explanation:

Value of x°=x°/(2x°+x°)×90°

= 1/3×90°

=30°

Value of 2x°=30°×2

=60°

4 0
3 years ago
Read 2 more answers
X -5x -14=0 quadratic formula
Oksanka [162]
No its a negitive number one x minus five x's equal -14
8 0
3 years ago
Which of the following points is a solution to the system of linear inequalities
Sergeu [11.5K]
For it to be a solution, it has to satisfy both inequalities...

subbing in (-4,-1)

2x + y < -5                           -x + y > 0
2(-4) - 1 < - 5                      -(-4) - 1 > 0
-8 - 1 < -5                              4 - 1 > 0
-9 < -5.....true                        3 > 0....true

solution is (-4,-1)

3 0
3 years ago
Read 2 more answers
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