If a polygon has 5 sides, then it is a regular pentagon
False: regular pentagon = equiangular. There are pentagons that have 5 sides that are not equiangular
Example
2^3 4^2
2×2×2=6 4×4=16
All you do is multiply the number by the exponent however many times the exponents is
Answer:
(w+7)(+9) I worked it out but not sure how to attach do yea
Step-by-step explanation:
(x , y) = (7, - 1)
2x + 3y = 11 → (1)
3x + 3y = 18 → (2)
subtracting (1) from (2) term by term eliminates the y- term
(3x - 2x) + (3y - 3y) = (18 - 11)
x + 0 = 7 ⇒ x = 7
substitute x = 7 into either of the 2 equations and solve for y
(1) → (2 × 7) + 3y = 11
14 + 3y = 11
subtract 14 from both sides
3y = 11 - 14 = - 3
divide both sides by 3
= - 1
solution is (7 , -1)
Answer: (i) 1 (ii) 3/4 , √3/3 (iii) 0 (iv) 1
<u>Step-by-step explanation:</u>
ΔRPQ is 1 30°-60°-90° triangle <em>because RQ = 2PQ</em> , where
(i) sin² (90°) = 1² = 1


(iii) sin (90°) × cos (90°) = 1 × 0 = 0
(iv) sin² (90°) - cos² (90°) = 1² - 0² = 1