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Vlada [557]
3 years ago
9

Based on the screenshot below which letter do you select to sort the items in an alphabetical order?

Computers and Technology
1 answer:
gladu [14]3 years ago
6 0

Answer:

the smallest number start with the first number of the alphabet

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Below is a recursive implementation of the factorial function. For what value of n will this function not produce the desired re
kompoz [17]

Answer:

Check the explanation

Explanation:

Here the data type we are making use of is int. Now when this function is being called for finding factorial of 13 or numbers that are greater than 13 then the function is expected to shows error and the desired result will not be produced.

Reason for this problem is-- range of int dat type is -2,147,483,648 to 2,147,483,647 . Now factorial of 12 is 47,90,01,600 which is less than 2,147,483,647 . But factorial of 13 is 6,22,70,20,800‬ which is greater than 2,147,483,647 which means int data type can not hold such large variable. That’s why it will not give desired result for value of n greater than 12.

Now you might just want to ask that what will function do in that case – the afct ins that different languages do different things in case of overflows. Some languages just say that data type can not handle . take for instance, when it comes to java warning about overflow is not there. And during overflow there it will show negative numbers.

3 0
4 years ago
He flow of electric charges through a material describes an electric _______.
almond37 [142]

Answer:

Its correct answer is D. Current

The flow of electric charges through a material describes an electric <u>Current.</u>

Explanation:

7 0
4 years ago
(PLEASE HELP!! I'll award brainiest!!)
Bas_tet [7]

Answer:

Repair

Have a good day

3 0
3 years ago
Read 2 more answers
Now suppose there are four links between source and destination (three routers in the path between source and destination). Each
pychu [463]

Answer:

12.1 seconds

Explanation:

Step 1:

Assuming the following data :

N: Size of packet = 30 Mb

T: Transmission rate =  10 Mbps

C: Speed of light in copper = 2 * 10^8 m/s

L: Length of link 5000 km

Step 2:

Calculation of the Transmission delay and the Propagation Delay

Transmission delay = \frac{packet size}{bandwidth} = \frac{30Mb}{10Mbps} = 3s

Propagation delay = \frac{length of link}{speed of light in copper} = \frac{5000*10^3}{2 * 10^8} = 0.025s

Step 3:

Calculation of the end-to -end delay

The end-to-end delay = 4*(Transmission Delay+Propagation Delay) = 4*(3+0.025) = 12.1 seconds

6 0
4 years ago
Describe at least five ways in which information technology can help students studying subjects other than computing
bija089 [108]

Answer:

yan lang po sana makatulong

5 0
3 years ago
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