Evaluate f(−3) for f(x)=2x2−x+5.
1 answer:
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Answer:
Hello,
<u>k=-3 and h=-2</u>
Step-by-step explanation:
h+1 is thus a root of x²+(-3-1)*x-5=0
x²-4x-5=0
x²+x-5x-5=0
x(x+1)-5(x+1)=0
(x+1)(x-5)=0
h+1=-1
<u>h=-2</u>
Answer:
Hello,
<u>k=-3 and h=-2</u>
Step-by-step explanation:
h+1 is thus a root of x²+(-3-1)*x-5=0
x²-4x-5=0
x²+x-5x-5=0
x(x+1)-5(x+1)=0
(x+1)(x-5)=0
h+1=-1
<u>h=-2</u>