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kumpel [21]
3 years ago
6

Correct I’ll give brainlist no links or I’ll report

Mathematics
1 answer:
Tatiana [17]3 years ago
4 0
Hi the answer is 4!!
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Ax+c/3=d solve for x
zvonat [6]
Ax +c/3 =d now we can make crisscross
ax+c =3d now find value of x
ax=3d-c positive c become negative when I turn to other equal side
so
ax=3d-c
x=3d_c/a
5 0
4 years ago
Hi! help is greatly appreciated!
devlian [24]

Answer:

answer is 3

because first we add 4+2=6

the sum of the line is 6 then we will got

x+3=6

x=6-3

x=3

Step-by-step explanation:

hope my answer is helpful to you

plz mark me as brainlist

6 0
4 years ago
Read 2 more answers
Hey can someone tell me why 132 is wrong? and help me with the right answer pls
andreev551 [17]

Answer:

∠CBA = 132

Step-by-step explanation:

Bisectors split up an angle into two identical angles

Thus, 7x - 11 = 2x + 44

This is the equation we will use to solve for x

7x - 11 = 2x + 44

step 1 add 44 to each side

44 + 11 = 55

-11 + 11 cancels out

we now have 7x = 2x + 55

step 2 subtract 2x from each side

7x - 2x = 5x

2x - 2x cancels out

we now have 5x = 55

step 3 divide each side by 5

5x / 5  = x

55 / 5 = 11

we're left with x = 11

The question is asking for the measure of ∠CBA

To find the measure of ∠CBA we plug in 11 for x in one of the given expressions and multiply that by 2 ( this is because the two angles are identical so there is no need to find the measures of both because ∠CBD≅∠ABD )

7(11) - 11

7 * 11 = 77

77 - 11 = 66

66 * 2 = 132

4 0
4 years ago
If Eight avocados cost $4. How much do 20 avocados cost?
Juliette [100K]

Answer:

$10

Step-by-step explanation:

divide $4 by 8. you get $.50. multiply that by 20 and you get $10

5 0
3 years ago
The radius of a circle is 19 kilometers. What is the circle's area?
Firdavs [7]
<h2> <em>Answer</em></h2>

<em>361</em><em>π</em><em>km²</em>

<h2> <em>Explanation</em></h2>

• the formula to find the area of a circle is A=πr²

<h3> => <em>A=π(19km)²</em></h3><h3><em>A=π(19km)² => A=361πkm</em>²</h3><h2><em>I</em><em> hope</em><em> it</em><em> helps</em><em>!</em><em>!</em></h2>

4 0
3 years ago
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