n, n + 2, n + 4 - three consecutive even integers
the twice the sum of the second and third: 2[(n + 2) + (n + 4)]
twelve less than six times the first: 6n - 12
The equation:
2[(n + 2) + (n + 4)] = 6n - 12
2(n + 2 + n + 4) = 6n - 12
2(2n + 6) = 6n - 12 <em>use distributive property</em>
(2)(2n) + (2)(6) = 6n - 12
4n + 12 = 6n - 12 <em>subtract 12 from both sides</em>
4n = 6n - 24 <em>subtract 6n from both sides</em>
-2n = -24 <em>divide both sides by (-2)</em>
n = 12
n + 2 = 12 + 2 = 14
n + 4 = 12 + 4 = 16
<h3>Answer: 12, 14, 16</h3>
8 litres (amount of 20% solution needed) and 7 litres for (amount of 50% solution needed)
<u>Step-by-step explanation:</u>
Let consider ‘x’ for 20% acid solution and (15 – x) for 50% acid solution. And so, the equation would be as below,
20% in x + 50% in (15 – x) = 15 litres of 34%
Convert percentage values, we get
0.20(x) + 0.50 (15 – x) = 15 (0.34)
0.20 x + 7.5 – 0.50 x = 5.1
-0.3 x + 7.5 = 5.1
0.3 x = 7.5 – 5.1
0.3 x = 2.4

Apply ‘x = 8’ value in (15 – x) we get,
15 – 8 = 7 litres
The value of 7 litres for (amount of 50% solution needed)
Answer:
look it up Answer:
Step-by-step explanation:
Step-by-step explanation:
Answer:
-8p ≥ -56
=> p ≤ 7
Step-by-step explanation: