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exis [7]
3 years ago
15

Please help me with this equation

Mathematics
1 answer:
vaieri [72.5K]3 years ago
7 0
You need to include a picture or an equation
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Slope :3 y-intercept :1
fiasKO [112]

Answer:

<em>y = 3x + 1</em>

Step-by-step explanation:

y = mx + b

The slope, or <em>m</em>, is 3.

The y-intercept, or <em>y</em>, is 1.

Plug them into the equation.

y = mx + b

<em>y = 3x + 1</em>

6 0
3 years ago
Read 2 more answers
40% of the students in a school band play brass instruments while 4 students play strings instruments
MaRussiya [10]
10 students (brass)=40% of band
4 students (strings)=16% of band 
? students (other)=44% rest of band
14/56%=?/44%
(cross multiply to find ?){don't forget to turn percents into decimals}
?=11
There are 25 students in total in the band.

5 0
4 years ago
Nora made 3 gallons of lemonade.
weqwewe [10]
Answer is b



Expiation
3 0
3 years ago
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If a phone cost $224 what would it cost if there was a 7% sales tax.
Annette [7]

Answer:

<u>$239.68</u>

Step-by-step explanation:

<u>Given</u>

  • Cost = $224
  • Sales Tax = 7%

<u>Solving</u>

  • Cost w/ Tax = Cost (1 + Tax)
  • Cost w/ Tax = 224 (1 + 0.07)
  • Cost w/ Tax = 224 * 1.07
  • Cost w/ Tax = <u>$239.68</u>
5 0
2 years ago
Suppose that in a senior college class of 500500 ​students, it is found that 179179 ​smoke, 228228 drink alcoholic​ beverages, 1
olga2289 [7]

Answer: a) 0.16, b) 0.058, and c) 0.856.

Step-by-step explanation:

Since we have given that

Number of students = 500

Number of students smoke = 179

Number of students drink alcohol = 228

Number of students eat between meals = 119

Number of students eat between meals and drink alcohol = 59

Number of students eat between meals and smoke = 72

Number of students engage in all three = 30

a) Probability that the student smokes but does not drink alcohol is given by

P(S-A)=P(S)-P(S\cap A)\\\\P(S-A)=\dfrac{179}{500}-\dfrac{99}{500}\\\\P(S-A)=\dfrac{179-99}{500}\\\\P(S-A)=\dfrac{80}{500}\\\\P(S-A)=0.16

b) eats between meals and drink alcohol but does not smoke.

P((M\cap A)-S)=P(M\cap A)-P(M\cap S\cap A)\\\\P((M\cap A)-S)=\dfrac{59}{500}-\dfrac{30}{500}\\\\P((M\cap A)-S)=\dfrac{59-30}{500}\\\\P((M\cap A)-S)=\dfrac{29}{500}\\\\P((M\cap A)-S)=0.058

c) neither smokes nor eats between meals.

P(S'\cap M')=1-P(S\cup M)\\\\P(S'\cap M')=1-\dfrac{72}{500}\\\\P(S'\cap M')=\dfrac{500-72}{500}\\\\P(S'\cap M')=\dfrac{428}{500}=0.856

Hence, a) 0.16, b) 0.058, and c) 0.856.

5 0
3 years ago
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