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Daniel [21]
3 years ago
12

Resuelvan me estás divisiones porfa:

Mathematics
1 answer:
faltersainse [42]3 years ago
6 0


72485÷7=10,355 53639÷61=879.327868852459

*4748÷59=80.47457627118644
*76835÷91=844.3406593406593

*33799÷44=768.1590909090909
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Write a multiplication expression using the following clues:
Akimi4 [234]

Answer:

1.1*8.3=9.13

Step-by-step explanation:

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Solve the equation using the multiplicative property of equality and the reciprocal. -2(a-5)=-1/2)10. (-1/2)(-2)(q-5)=(-1/2)10.
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Place value for 987,164.302
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9 is in the hundred thousands place, 8 is in the ten thousands place, 7 is in the thousands place, 1 is in the hundreds place, 6 is in the tens place, 4 is in the ones place.
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3 years ago
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You are given the information that P(A) = 0.30 and P(B) = 0.40.
Ad libitum [116K]

Answer:

1.B. No. You need to know the value of P(A and B). 2.C. Yes P(A and B) =0, so P(A or B) = P(A) + P(B).

Step-by-step explanation:

We can solve this question considering the following:

For two mutually exclusive events:

\\ A_{1}\;and\;A_{2}

\\ P(A_{1} or A_{2}) = P(A_{1}) + P(A_{2}) (1)

An extension of the former expression is:

\\ P(A_{1} or A_{2}) = P(A_{1}) + P(A_{2}) - P(A_{1} and A_{2}) (2)

In <em>mutually exclusive events,</em> P(A and B) = 0, that is, the events are <em>independent </em>one of the other, and we know the probability that <em>both events happen</em> <em>at the same time is zero</em> (P(A <em>and</em> B) = 0). There are some other cases in which if event A happens, event B too, so they are not mutually exclusive because P(A <em>and</em> B) is some number different from zero. Notice the difference between <em>OR</em> and <em>AND. The latter implies that both events happen at the same time.</em>

In other words, notice that the formula (2) provides an extension of formula (1) for those events that are not <em>mutually exclusive</em>, that is, there are some cases in which the events share the same probabilities in a way that these probabilities <em>must be subtracted</em> from the total, so those probabilities in common do not "inflate" the actual probability.

For instance, imagine a person going to a gas station and ask for checking both a tire and lube oil of his/her car. The probability for checking a tire is P(A)=0.16, for checking lube oil is P(B)=0.30, and for both P(A and B) = 0.07.

The number 0.07 represents the probability that <em>both events occur at the same time</em>, so the probability that this person ask for checking a tire or the lube oil of his/her car is:

P(A or B) = 0.16 + 0.30 - 0.07 = 0.39.

That is why we cannot simply add some given probabilities <em>without acknowledging if the events are or not mutually exclusive</em>, whereas we can certainly add the probabilities in question when we know that both probabilities are <em>mutually exclusive</em> since P(A and B) = 0.

In conclusion, knowing the events are mutually exclusive <em>does</em> provide <em>extra information</em> and we can proceed to simply add the probabilities of either event; thus, the answers are those in which <em>we need to previously know the value of P(A and B)</em>.  

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3 years ago
What is special about a 30 60 90 triangle?
Nata [24]
A 30-60-90 triangle is special because of the relationship of its sides. Also <span>It turns out that in a 30-60-90 triangle, you can find the measure of any of the three sides, simply by knowing the measure of at least one side in the triangle.

Hope this helps. :)</span>
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