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leonid [27]
3 years ago
11

A MOVIE THEATRE HAS TWO ROOMS. ROOM A HAS 9 ROWS WITH 18 SEATS IN EACH ROW. ROW B HAS THREE TIMES AS MANY SEATS AS ROOM A. HOW M

ANY SEATS ARE THERE IS BOTH ROOMS?
Mathematics
1 answer:
Oduvanchick [21]3 years ago
7 0
Pretty sure it’s 162
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The crafting club sold art calendars for a recent fundraiser. The table below lists the number of calendars sold by each member
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Answer:

there is no table below, you have to add a picture

Step-by-step explanation:

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3 years ago
PLEASE HELP ASAP<br> Find the missing side lengths.
zimovet [89]
You can see it’s 90

You can also see it because. A triangle is 180 degrees so

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3 years ago
If you place a 20 ft ladder 4ft from the base of the wall. How high up will it reach? Round answer to the nearest tenth
xeze [42]

Answer:

h = 19.6 ft

Step-by-step explanation:

Given that,

A 20 ft ladder 4ft from the base of the wall.

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We need to find the height of the reach. Let it is P.

Using Pythagoras theorem,

H^2=b^2+P^2\\\\P=\sqrt{H^2-b^2}\\\\P=\sqrt{20^2-4^2}\\\\=19.59\ ft

or

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7 0
3 years ago
Graph XY with endpoints X(5,−2) and Y(3,−3) and its image after a reflection in the x-axis and then a rotation of 270 degrees ab
DerKrebs [107]

Answer:

  X''(2, -5), Y''(3, -3)

Step-by-step explanation:

You know that reflection in the x-axis changes the sign of the y-coordinate. Points that used to be above the axis are now below by the same amount, and vice versa.

Rotation counterclockwise by 270° is the same as clockwise rotation by 90°. That maps the coordinates like this:

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The two transformations together give you ...

  (x, y) ⇒ (x, -y) ⇒ (-y, -x) . . . . . . . . equivalent to reflection across y=-x.

Using this mapping, we have ...

  X(5, -2) ⇒ X''(2, -5)

  Y(3, -3) ⇒ Y''(3, -3) . . . . . . on the equivalent line of reflection, so invariant

_____

The attachment shows the original segment in red, the reflected segment in purple, and the rotated segment in blue. The equivalent line of reflection is shown as a dashed green line.

8 0
3 years ago
Use the compass and ruler to construct the bisector of the angle given below.
rodikova [14]
Oh my. ALEKS brings back terrible memories, but I hope you managed to do this. You should’ve drawn a line splitting the angle perfect in two. I’m not exactly certain how to use the tool as I’ve never really gotten to to that topic, but I hope you did well. :)
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3 years ago
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