Answer:
Angle A is 29 degress Angle B is 61 Angle C is 90
Side AB is 5.8 Side BC is 2.8 and Side AC is 5.1
Step-by-step explanation:
Angle A is found using triangle interior theorem.
I found side AC by using law of sines
b/sin b= c/sin c
x/sin 61= 5.8/sin 90( which equal 1)
x=5.1
I found side BC by using pythagoren theorem.
a^2 + b^2=c^2
5.1^2+ b^2=5.8^2
26.01+b^2=36.64
b^2=7.63
b=approx 2.8.
Answer:
9
Step-by-step explanation:
You have the correct axis of symmetry value. Nice work.
Plug that x value into the equation to get...
y = -2x^2 - 12x - 10
y = -2*(-3)^2 - 12*(-3) - 10 <<-- replace every x with -3; then use PEMDAS
y = -2*(9) - 12*(-3) - 10
y = -18 + 36 - 10
y = 18 - 10
y = 8
The vertex is the ordered pair (-3, 8)
Note: the axis of symmetry is the vertical line through the vertex
Answer:
12
Step-by-step explanation:
Answer:
- y = -5x +10
- (0, 10)
- (1, 5)
- see attached
Step-by-step explanation:
1. Subtract 5x from both sides to put the equation in slope-intercept form:
y = -5x +10
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2. The y-intercept is the point corresponding to x=0. The y-value when x=0 is the constant in the equation: 10. Then the point is ...
(x, y) = (0, 10)
You may notice this is one of the points listed in part 4, and is also used in question 3.
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3. The x-value computed is 1; the y-value computed is 5. The point is ...
(x, y) = (1, 5)
You may notice this is one of the points listed in part 4.
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4. See attached
