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mina [271]
3 years ago
6

HELP PLSSSSSSSSSSSSSSA PLSSSSS

Mathematics
2 answers:
pentagon [3]3 years ago
4 0

Answer:

Figure 1: x = 120°

Figure 2: x = 54°

Figure 3: x = 64°

Step-by-step explanation:

Every triangles interior angles will add up to 180°

Figure 1: 30 + 30 + x = 180

60 + x = 180

x = 120

Figure 2: 104 + 22 + x = 180

126 + x = 180

x = 54

Figure 3:

part 1: 154 + z = 180

z = 26

part 2: 90 + 26 + x = 180

116 + x = 180

x = 64

BartSMP [9]3 years ago
3 0

Answer:

1. 120

2. 54

3. 64

Step-by-step explanation:

1.

   30 + 30 = 60

   180-60 = 120

2.

    104 + 22 = 126

    180 - 126 = 54

3.

    180 - 154 = 26

    26 + 90 = 116

    180 - 116 = 64

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N equals eight what is the value of 56 divided by n
PilotLPTM [1.2K]

Answer:7

Step-by-step explanation:

N=8

Divide:56/8=7

3 0
3 years ago
About what percent of all cans sold contained tuna-flavored food?
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4 0
3 years ago
Given the set points K+1:(-1,8),(1,0) and (2,5), find the quadratic polynomial interpolate
Sauron [17]

Answer:

The interpolating polynomial is p(x) = 1-4x+3x^2.

Step-by-step explanation:

We want to find a quadratic polynomial p(x) such that p(-1)=8, p(1)=0 and p(2)=5. In order to do this let us write p(x) = a_0+a_1x+a_3x^2.

Now, evaluating the polynomial in the points -1, 1 and 2 we get

\begin{cases} 8 = p(-1) &= a_0-a_1+a_2\\ 0 = p(1) &= a_0+a_1+a_2\\ 5 = p(2) &= a_0+2a_1+4a_2\end{cases}

This relations give us a linear system of equations:

\begin{cases} 8 &= a_0-a_1+a_2\\ 0 &= a_0+a_1+a_2\\ 5&= a_0+2a_1+4a_2\end{cases}

where the a_0, a_1 and a_2 are the unknowns.

The augmented matrix of the system is

\begin{pmatrix}1 & -1 & 1 & 8\\ 1 & 1 & 1 & 0\\ 1 & 2 & 4 & 5\end{pmatrix}

In this matrix it is easy to eliminate the 1's of the first column and get

\begin{pmatrix} 1 & -1 & 1 & 8\\ 0 & 2 & 0 & -8\\ 0 & 3 & 3 & -3\end{pmatrix}

From this matrix we can find the values of each unknown. Notice that the second row gives us 2a_2=-8 that yields a_1=-4.

Then, the third row means 3a_1+3a_2=-3 that gives -12+3a_2=-3. So, a_2=3.

Finally, the first row is a_0-a_1+a_2=8 and substituting is a_0+7=8 that yields a_0=1.

Therefore, the interpolating polynomial is

p(x) = 1-4x+3x^2.

8 0
3 years ago
Can someone help me with this substitution method for algebra Y=4*-3x 5x-y=22
alexira [117]
y=4-3x\\
5x-y=22\\\\
5x-(4-3x)=22\\
5x-4+3x=22\\
8x=26\\
x=\dfrac{26}{8}=\dfrac{13}{4}\\\\
y=4-3\cdot\dfrac{13}{4}\\
y=4-\dfrac{39}{4}\\
y=\dfrac{16}{4}-\dfrac{39}{4}\\
y=-\dfrac{23}{4}\\\\
\boxed{(x,y)=\left(\dfrac{13}{4},-\dfrac{23}{4}\right)}
7 0
3 years ago
20-3•6+10^+(6+1)•4<br> Show your work with an explanation of what step you are on
weeeeeb [17]

Remember to follow PEMDAS (Parenthesis, Exponents (&roots), Multiplication, Division, Addition, Subtraction)

20-3•6+10²+(6+1)•4

First, solve the parenthesis

6 + 1 = 7

20 - 3 x 6 + 10² + 7 x 4

Next, solve the exponent

10² = 10 x 10 = 100

20 - 3 x 6 + 100 + 7 x 4

Next, solve each multiplication. Remember to bring your sign.

-3 x 6 = -18

7 x 4 = 28

20 - 18 + 100 +28

Simplify

(20 - 18) + (100 + 28)

2 + 128

130

130 is your answer

hope this helps

6 0
4 years ago
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