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3 years ago

What is the difference of the polynomials?

Mathematics

1 answer:

drek231 [11]3 years ago

6 0

Answer:

In mathematics, in the area of complex analysis, the general difference polynomials are a polynomial sequence, a certain subclass of the Sheffer polynomials, which include the Newton polynomials, Solberg's polynomials, and the Stirling interpolation polynomials as special cases.

Step-by-step explanation:

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1) Miguel has a gift card to an electronics store. He has $ 150 on the card. He purchased a DVD for $ 20 and some games for $12.

GrogVix [38]

Answer:

9 games

Step-by-step explanation:

If he purchase 1 game, he spent $12.50. If he purchased 2 games, he spent 2(12.50) = $25.

This means he spent 12.5x for x number of games.

His total spending will be 12.5x + 20. He has $17.50 left on the card from $150.

150 - (12.5x + 20) = 17.5

150 - 12.5x -20 = 17.5

130 - 12.5x = 17.5

-12.5x = 17.5 - 130

-12.5x = -112.5

x = 9

8 0

3 years ago

20 Points! <br><br> Solve for x

Marrrta [24]

Answer:

so all x's have to be added together.

8x+5x+10x+7x=30x

-2+3=1

1dividedby30=30

x=30

hope this helps

7 0

3 years ago

Read 2 more answers

PLZ HELP ME! 100 points for person who answers quickly!

Advocard [28]

(-1.15)x3.2=

-3.68

Alright so I got -3.68 by multiplying -1.15x3.2. We get a negative number since the first number is negative.

3 0

2 years ago

Use the following table for questions 11-13.A baseball manager believes a linear relationship exists between the number of Home

slamgirl [31]

The regression equation of Y on X is given by the following formula:

$Y-\bar{Y}=b_{yx}(X-\bar{X})$

Where byx is given by the formula:

$b_{yx}=\frac{N\sum^{}_{}XY-\sum^{}_{}X\sum^{}_{}Y}{N\sum^{}_{}X^2-(\sum^{}_{}X)^2}$

Where N is the number of values (N=8). We need to find the sum of X values, the sum of Y values, the average of X, the average of Y, the sum of X*Y and the sum of X^2.

The table of values is:

The values we need to know are on the following table:

By replacing the known values in the formula we obtain:

$\begin{gathered} b_{yx}=\frac{8\cdot26125-167\cdot995}{8\cdot4649-(167)^2} \\ b_{yx}=\frac{209000-166165}{37192-27889} \\ b_{yx}=\frac{42835}{9303} \\ b_{yx}=4.6 \end{gathered}$

Now, the average of X and Y is the sum divided by N, then: