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Svetllana [295]
3 years ago
8

CONDITIONAL PROBABILITY ASSISTANCE

Mathematics
1 answer:
Mars2501 [29]3 years ago
4 0

Consider such events:

A - selected student is freshmen

B - selected student is girl

A\cap B - selected student is freshman is girl

A|B - choosen girl is freshmen.

Use formula Pr(A|B)=\dfrac{Pr(A\cap B)}{Pr(B)}.

From the table you can see that girls that are freshmen are 4 from all 30 people, then Pr(A\cap B)=\dfrac{4}{30}. There are 18 girls, then Pr(B)=\dfrac{18}{30}. Substitute into the formula:

Pr(A|B)=\dfrac{\frac{4}{30} }{\frac{18}{30} }=\dfrac{4}{18} =\dfrac{2}{9}.

Answer: Pr(A|B)=\dfrac{2}{9}.

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3 0
3 years ago
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