28 units cubed I believe to be the right answer
Answer:
(a) = 13,500
(b) = 2,250
Step-by-step explanation:
Matching Step 3 with Step 2, we see that ...
(a) = 3x^2·y
(b) = 3x·y^2
Filling in the values given for x and y, we have ...
(a) = 3·30^2·5 = 13,500
(b) = 3·30·5^2 = 2,250
Answer:
It's option c. 1/6y + 1/6(y + 12) - 2
I'm sorry if it's wrong, have a great day.
<span>We use the Pythagoras Theorem to derive a formula for finding the distance
between two points in 2- and 3- dimensional space.</span>
Let
P<span> = (x 1, y 1) </span>
Q<span> = (x 2, y 2) </span>
be two points on the Cartesian plane
<span>Then
from the Pythagoras Theorem we find that the distance between P and Q is</span>
PQ=((x2-x1)^2+(y2-y1)^2)^0.5
In a
similar way
it can
be proved that if
P<span> = (x 1, y 1, z1) and </span>
Q<span> = (x 2, y 2, z2) are two
points in the 3-dimensional space, </span>
<span>the
distance between P and Q is</span>
PQ=((x2-x1)^2+(y2-y1)^2+(z2-z1)^2)^0.5
<span>
</span>
