Answer:
Yes
Step-by-step explanation:
8 73/
100=8.73
Answer:
1.1h+0.75c=4.55---------------1
h+c=5--------------2
Step-by-step explanation:
Step one:
given data
total lunch items= 5
let hot dogs be h
and cookies be c
cost of hot dogs = $1.10
cost of cookies = $0.75
total cost = $4.55
Step two:
The linear model for the total cost is given as
4.55=1.1h+0.75c---------------1
and the model for the number of items is
h+c=5--------------2
The systems of the equation for the situation is
1.1h+0.75c=4.55---------------1
h+c=5--------------2
A^8/a^3=a^5 you subtract the exponents
Answer: The number of first-year residents she must survey to be 95% confident= 263
Step-by-step explanation:
When population standard deviation (
) is known and margin of error(E) is given, then the minimum sample size (n) is given by :-
, z* = Two-tailed critical value for the given confidence interval.
For 95% confidence level , z* = 1.96
As, = 8.265, E = 1
So, ![n= (\dfrac{1.96\times8.265}{1})^2 =(16.1994)^2\\\\= 262.42056036\approx263\ \ \ [\text{Rounded to the next integer}]](https://tex.z-dn.net/?f=n%3D%20%28%5Cdfrac%7B1.96%5Ctimes8.265%7D%7B1%7D%29%5E2%20%3D%2816.1994%29%5E2%5C%5C%5C%5C%3D%20262.42056036%5Capprox263%5C%20%5C%20%5C%20%5B%5Ctext%7BRounded%20to%20the%20next%20integer%7D%5D)
Hence, the number of first-year residents she must survey to be 95% confident= 263
only 1 time....because 20 divided by 16 is 1 r4
