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Harman [31]
2 years ago
11

Which equation can be used to determine the value of x?

Mathematics
2 answers:
lorasvet [3.4K]2 years ago
7 0

Answer:

(3x + 18) + 93 = 180

23 + X

Step-by-step explanation:

(3x + 18) + 93 = 180, its supplymentery

180 - 93 = 87

87 - 18 = 69

3x = 69

69/3 = 23

23 = X

Otrada [13]2 years ago
6 0

Answer:

Step-by-step explanation:

Remark

You have to assume nothing you should have to assume. You have to assume that 93 degrees on 3x + 18 sit on the same straight line. If it just looks that way, you are on shaky ground. You must be told. It's a good thing to keep in mind. Likely you'll get more questions like this. Just be aware you should not have to assume anything to make the problem work.

If the two angles both have one leg on what is marked as a straight line, then the sum of the two angles must = 180

Solution

The first one is not true. 3x + 18 is smaller than 90 degrees because 93 is more than 90 degrees. If A is true then the line is bent a bit.

B is not true. We just found one equation that doesn't work.

C is not true either. The result of trying to solve C will make x minus because 93>90 and 18 when subtracted  makes 3x even more minus.

D is true

(3x + 18) + 93 = 180               Subtract 93 from both sides.

(3x + 18) + 93-93 = 180 - 93   Combine

(3x + 18) = 87                           Remove the brackets

3x + 18 = 87                             Subtract 18

3x+18-18 = 87-18                

3x = 69                                    Divide by 3

3x/3 = 69/3

Answerx = 23

E is not true because D is true.

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mote1985 [20]

Answer:

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And rounded up we have that n=8068

Step-by-step explanation:

The margin of error for the proportion interval is given by this:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

We want for this case a 95% of confidence desired, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The margin of error for this case is ME =\pm 0.01 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

The estimated proportion for this case is \hat p=0.3. And replacing into equation (b) the values from part a we got:

n=\frac{0.3(1-0.3)}{(\frac{0.01}{1.96})^2}=8067.36  

And rounded up we have that n=8068

7 0
3 years ago
Doug hits a baseball straight towards a 15 ft high fence that is 400 ft from home plate. The ball is hit 2.5ft above the ground
Scorpion4ik [409]

Answer:

125.4\ \text{m/s}

Step-by-step explanation:

u = Initial velocity of baseball

\theta = Angle of hit = 30^{\circ}

x = Displacement in x direction = 400 ft

y = Displacement in y direction = 15 ft

y_0 = Height of hit = 2.5 ft

a_y = g = Acceleration due to gravity = 32.2\ \text{ft/s}^2

t = Time taken

Displacement in x direction

x=u_xt\\\Rightarrow x=u\cos\theta t\\\Rightarrow t=\dfrac{x}{u\cos\theta}\\\Rightarrow t=\dfrac{400}{u\cos30^{\circ}}\\\Rightarrow t=\dfrac{400}{u\dfrac{\sqrt{3}}{2}}\\\Rightarrow t=\dfrac{800}{u\sqrt{3}}

Displacement in y direction

y=y_0+u_yt+\dfrac{1}{2}a_yt^2\\\Rightarrow y=y_0+u\sin\theta t+\dfrac{1}{2}a_yt^2\\\Rightarrow 15=2.5+u\sin30^{\circ}(\dfrac{800}{u\sqrt{3}})+\dfrac{1}{2}\times -32.2\times (\dfrac{800}{u\sqrt{3}})^2\\\Rightarrow \dfrac{400}{\sqrt{3}}-\dfrac{10304000}{3u^2}-12.5=0\\\Rightarrow 218.44=\dfrac{10304000}{3u^2}\\\Rightarrow u=\sqrt{\dfrac{10304000}{3\times218.44}}\\\Rightarrow u=125.4\ \text{m/s}

The minimum initial velocity needed for the ball to clear the fence is 125.4\ \text{m/s}

5 0
3 years ago
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zhuklara [117]

Answer:

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Step-by-step explanation:

These two terms are what we call, 'like terms'. This means that they are terms whose variables and exponents are the same. 14w^9- 19w^9 have the variable w^9 in common.

In these cases, all we do is use the coefficients (the number in front of the variable). Hence, 14w^9- 19w^9, quite literally turns into, 14-19. If we complete the sum, 14-19= -5. Put it all together, we have -5w^9.

Hope this helps!

4 0
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we have the equation:-

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You have 19 digs for your current volleyball season. There are 5 games left in the season. You want to break your previous recor
Charra [1.4K]

Answer:We must get more than 7 digs in the remaining 5 games  to break record of 26.


Step-by-step explanation:

Given situation:- Let  x represents the number of digs which we must get in the remaining 5 games to break your record ,and we have 19 digs for our current volleyball season.

To break  previous record of 26 digs in a season, we have to get more than 26 i.e. 19 digs added to x must be greater than 26

⇒x+19 ≥ 26

⇒x≥26-19⇒x≥7

Therefore,we must get more than 7 digs in the remaining 5 games  to break record of 26.


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3 years ago
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