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professor190 [17]
3 years ago
14

Write the following as an inequality. x is greater than 4 and less than or equal to 8 Use x only once in your inequality. pls hu

rry i will give brainlist​
Mathematics
1 answer:
Lapatulllka [165]3 years ago
6 0

Answer:

8>_x>4

>_ this is greater than equal to symbol eight is greater than or equal to x is greater than 4

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If no number can be used more than once, how many different 2-digit numbers can be formed from the digits 4, 6, and 8?
ikadub [295]

Answer:

Six.

46

48

64

68

84

86

Step-by-step explanation:

hoped this helped!

4 0
3 years ago
If the math club collected 17,604 points and gave away 36 shirts, how many points were collected if 82 shirts were given away?
luda_lava [24]
17,604 points/36 shirts=<span>489 points per shirt
</span>82 shirts*489 points=<span>40,098 points</span>
4 0
3 years ago
Please could I have some help :)
nirvana33 [79]

Answer:

a) x = 128 degrees

b) Angle APD is the arc angle, which is equal to the central angle x subtended by the arc.  Therefore angle APD = 128 degrees (and not 116 degrees)

Step-by-step explanation:

Given:

attached diagram

ABC is a straight line

Solution:

a) Find x

ABC is a straight line

angle ABD = supplement of CBD = 180-CBD = 180-116 = 64 degrees.

x is the central angle of the arc APD

so angle ABD is the inscribed angle which equals half of the arc angle =>

angle ABD = x/2 = 64 degrees

Solve for x

x/2 = 64

x = 2*64

x = 128 degrees

b.

Angle APD is the arc angle, which is equal to the central angle x subtended by the arc.  Therefore angle APD = 128 degrees (and not 116 degrees)

5 0
3 years ago
Read 2 more answers
The 2nd, 6th, 8th terms of an A.P. form a G.P. , find the common ratio and the general term of the G.P.​
melisa1 [442]

The terms of an arithmetic progression, can form consecutive terms of a geometric progression.

  • The common ratio is: \mathbf{r = \frac{a + 5d}{a + d}}
  • The general term of the GP is: \mathbf{a_n = (a + d) \times (\frac{a + 5d}{a + d})^{n-1}}

The nth term of an AP is:

\mathbf{T_n = a + (n - 1)d}

So, the <em>2nd, 6th and 8th terms </em>of the AP are:

\mathbf{T_2 = a + d}

\mathbf{T_6 = a + 5d}

\mathbf{T_8 = a + 7d}

The <em>first, second and third terms </em>of the GP would be:

\mathbf{a_1 = a + d}

\mathbf{a_2 = a + 5d}

\mathbf{a_3 = a + 7d}

The common ratio (r) is calculated as:

\mathbf{r = \frac{a_2}{a_1}}

This gives

\mathbf{r = \frac{a + 5d}{a + d}}

The nth term of a GP is calculated using:

\mathbf{a_n = a_1r^{n-1}}

So, we have:

\mathbf{a_n = (a + d) \times (\frac{a + 5d}{a + d})^{n-1}}

Read more about arithmetic and geometric progressions at:

brainly.com/question/3927222

6 0
3 years ago
PLS HALP I'm stuck on number 31
Marta_Voda [28]
There are 2 possibilities for where A can be: one where C is 30° (and A is 60°) and another where C is 60° (and A is 30°). Since it's not specified, we can find both.

30°:
drawing the triangle on a graph, you can see that point C is 4 units above point B, so we know that one side of the triangle is 4. Once we find the other "leg" of the triangle (the one that's parallel to the x-axis), we can just add that value to B to find the x coordinate of A.
If angle C is 30°, using the side ratios of a 30-60-90 triangle, that side is "a√3", and the side we're looking for is a. So, to find a, we just divide 4 by √3. In that case, point A is 4/(√3) units to the right of -2√3. We can rationalize 4/(√3) like this:

(4√3)/3

and then add that to 2√3:

(4√3)/3 + -2√3

(4√3)/3 + (-6√3)/3 = (-2√3)/3

We know that the x-coordinate of A is (-2√3)/3, and the y-coordinate is -1 because B is a right angle and we're just moving horizontally. So, if C is 30° and A is 60°, point A is at ((-2√3)/3, -1).

60°:
in this case, the leg we know is "a" and the leg we're looking for is "a√3". So, we can multiply 4 by √3 to get the distance from B:

4 x √3 = 4√3

4√3 + -2√3 = 2√3

So the x-coordinate of A here is 2√3, and the y-coordinate is still -1: (2√3, -1).

hope that helps! if you liked this answer please rate it as brainliest!! thank you!!!

8 0
3 years ago
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