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serious [3.7K]
2 years ago
9

A normal curve is ___________ about the mean. consequently, 50% of the total area under a normal distribution curve lies on the

left side of the mean, and 50% lies on the right side of the mean.

Mathematics
1 answer:
kozerog [31]2 years ago
8 0
In statistics, when you gather data points for the same test, you construct a distribution graph. For example, you make a statistics based on the score of a class for a 145-item test. You graph it based on frequency such as, 10 students got 50 points and so and so forth. When that test have a few outliers and have more or less the same score, you form a normal distribution graph. It is more commonly known as the Gaussian Bell Curve. An example would be shown in the picture.

A normal distribution curve is symmetric about the mean. As a result, the area under the curve on the left side of the mean would be equal to the area under the curve on the right side of the mean. So, each would constitute 50%.

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A student was given two data sets, Set A and Set B. Which of the following
Elden [556K]

Answer:

I don't know were the statement are but here are the specs of each set

Step-by-step explanation:

Set A

mean; 83.83333

median; 87.5

mode; it has no mode

range; 147

Set B

mean; 67.08571

median; 3

mode; no mode

range; 376

hope this helps sorry for late answer :)

5 0
2 years ago
What is .38 into a fraction
Alona [7]

<em>Your answer is the following.</em>

<em></em>

<em>Answer = 19/50 </em>

<em />

5 0
3 years ago
Read 2 more answers
Identify the domain and range of the relation:<br> (-5,-3), (-2,1), (1,4), (2,5)
jonny [76]

Domain is the x-coordinate and range is the y - coordinate

\therefore \: domain =  \{ - 5, \:  - 2, \: 1, \: 2 \} \\  \\ \&\: range =  \{  - 3, \: 1, \: 4, \: 5\}

3 0
3 years ago
For which rational expression is 8 an excluded value ? check all that apply
denis23 [38]

<u>Answer:</u>

The correct answer options are C. \frac{x^2+5}{x-8} and D. \frac{x^2-x-56}{x^2-64}.

<u>Step-by-step explanation:</u>

The values which make the denominator equal to zero are called the excluded values.

Here, we can substitute 8 for x and check if it makes the denominator 0.

\frac{x-8}{x+8} = \frac{8-8}{8+8} =\frac{0}{16} =0

\frac{x-2}{x^2-4} = \frac{8-2}{8^2-4} =\frac{6}{60} =\frac{1}{10}

\frac{x^2+5}{x-8} = \frac{8^2+5}{8-8} =\frac{69}{0}

\frac{x^2-x-56}{x^2-64} = \frac{8^2-8-56}{8^2-64} = \frac{0}{0} =0

\frac{8x^2-2}{x^2-16} = \frac{8(8)^2-2}{8^2-16} =\frac{510}{48}

7 0
3 years ago
What is the slope of the line that passes through the points (3, -2) and (9, -2)?
ICE Princess25 [194]

m=(-2+2)/(9-6)=0/3=0

m=0

7 0
3 years ago
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