A normal curve is ___________ about the mean. consequently, 50% of the total area under a normal distribution curve lies on the
left side of the mean, and 50% lies on the right side of the mean.
1 answer:
In statistics, when you gather data points for the same test, you construct a distribution graph. For example, you make a statistics based on the score of a class for a 145-item test. You graph it based on frequency such as, 10 students got 50 points and so and so forth. When that test have a few outliers and have more or less the same score, you form a normal distribution graph. It is more commonly known as the Gaussian Bell Curve. An example would be shown in the picture.
A normal distribution curve is symmetric about the mean. As a result, the area under the curve on the left side of the mean would be equal to the area under the curve on the right side of the mean. So, each would constitute 50%.
A normal distribution curve is symmetric about the mean. As a result, the area under the curve on the left side of the mean would be equal to the area under the curve on the right side of the mean. So, each would constitute 50%.
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We can set it up like this, where <em>s </em>is the speed of the canoeist:
To make a common denominator between the fractions, we can multiply the whole equation by s(s-5):
![s(s-5)[\frac{18}{s} + \frac{4}{s-5} = 3] \\ 18(s-5)+4s=3s(s-5) \\ 18s - 90+4s=3 s^{2} -15s](https://tex.z-dn.net/?f=s%28s-5%29%5B%5Cfrac%7B18%7D%7Bs%7D%20%2B%20%5Cfrac%7B4%7D%7Bs-5%7D%20%3D%203%5D%20%5C%5C%2018%28s-5%29%2B4s%3D3s%28s-5%29%20%5C%5C%2018s%20-%2090%2B4s%3D3%20s%5E%7B2%7D%20-15s)
If we rearrange this, we can turn it into a quadratic equation and factor:
Technically, either of these solutions would work when plugged into the original equation, but I would use the second solution because it's a little "neater." We have the speed for the first part of the trip (9 mph); now we just need to subtract 5mph to get the speed for the second part of the trip.
The canoeist's speed on the first part of the trip was 9mph, and their speed on the second part was 4mph.
To make a common denominator between the fractions, we can multiply the whole equation by s(s-5):
If we rearrange this, we can turn it into a quadratic equation and factor:
Technically, either of these solutions would work when plugged into the original equation, but I would use the second solution because it's a little "neater." We have the speed for the first part of the trip (9 mph); now we just need to subtract 5mph to get the speed for the second part of the trip.
The canoeist's speed on the first part of the trip was 9mph, and their speed on the second part was 4mph.