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kati45 [8]
3 years ago
7

2) As a wildlife biologist you are currently researching feral pigs in Texas and need to collect data to yield the average weigh

t of a mature female feral pig in Texas. Which type of study is most suitable for data collection in this situation? A) experimental B) Census sampling Eliminate D) simulation​
Mathematics
1 answer:
jonny [76]3 years ago
6 0

Answer:

Step-by-step explanation:

C sampling

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4•(-24)-3 You don't need any parenthesis because it's order of operations
5 0
3 years ago
Darin has 5 coins that the total 62%. What are the coins?
Snowcat [4.5K]
Hi there!

There are several possible options.

A main one would be : 10 DIMES and 2 PENNIES

Other ones could be :

2 quarters
1 dime
2 pennies

62 pennies

12 nickels
2 pennies

and more !

Hope this helps !
5 0
3 years ago
How do u do 6x32 and 7x29 using distribuative property to solve
Rufina [12.5K]

Answer:

use multiple the numbers to get the co rrect

Step-by-step explanation:

32×6

=192

29×7=203

4 0
3 years ago
Read 2 more answers
Which graph represents the solution to the given system ? Y=- 6X - 2Y +2=- 6X
Nonamiya [84]

Answer: The graph is attached.

Step-by-step explanation:

The equation of the line in Slope-Intercept form is:

y=mx+b

Where "m" is the slope and "b" is the y-intercept.

Given the first equation:

y=- 6x - 2

You can identify that:

m=-6\\b=-2

 By definition, the line intersects the x-axis when y=0. Then, subsituting this value into the equation and solving for "x", you get that the x-intercept is:

0=- 6x - 2\\\\2=-6x\\\\x=-\frac{1}{3}\\\\x=-0.333

Now you can graph it.

Solve for "y" from the second equation:

y +2=- 6x\\\\y=-6x-2

 You can identify that:

m=-6\\b=-2

Notice that the slopes and the y-intercepts of the first line and the second line are equal; this means that they are exactly the same line and the System of equations  has<u> Infinitely many solutions.</u>

See the graph attached.

4 0
3 years ago
Help with 21 would be much appreciated.
umka2103 [35]

Answer:

\large\boxed{x=2\sqrt{21}\ and\ y=4\sqrt3}

Step-by-step explanation:

Look at the picture.

ΔADC and ΔCDB are similar. Therefore the sides are in proportion:

\dfrac{AD}{CD}=\dfrac{CD}{DB}

We have

AD=14-8=6\\CD=y\\DB=8

Substitute:

\dfrac{6}{y}=\dfrac{y}{8}         <em>cross multiply</em>

y^2=(6)(8)

y^2=48\to y=\sqrt{48}\\\\y=\sqrt{16\cdot3}\\\\y=\sqrt{16}\ cdot\sqrt3\\\\\boxed{y=4\sqrt3}

For x use the Pythagorean theorem:

x^2=6^2+(4\sqrt3)^2\\\\x^2=36+48\\\\x^2=84\to x=\sqrt{84}\\\\x=\sqrt{4\cdot21}\\\\x=\sqrt4\cdot\sqrt{21}\\\\\boxed{x=2\sqrt{21}}

3 0
3 years ago
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