Answer:
The missing statement is ∠ACB ≅ ∠ECD
Step-by-step explanation:
Given two lines segment AC and BD bisect each other at C.
We have to prove that ΔACB ≅ ΔECD
In triangle ACB and ECD
AC=CE (Given)
BC=CD (Given)
Now to prove above two triangles congruent we need one more side or angle
so, as seen in options the angle ∠ACB ≅ ∠ECD due to vertically opposite angles
hence, the missing statement is ∠ACB ≅ ∠ECD
Answer:
I/d/k but I will say 9/10
Step-by-step explanation:
Wow
Answer:
39,51
Step-by-step explanation:
Complementary angles add to 90 degrees
Let one angle be x
The other angle is x+12
x+ x+12 = 90
Combine like terms
2x+12 = 90
Subtract 12 from each side
2x+12-12 = 90-12
2x = 78
Divide each side by 2
2x/2 = 78/2
x =39
The other angle is 39+12 =51
<em>Greetings from Brasil... </em>
A 1st degree function can be written in two ways:
F(X) = AX + B
or
Y = AX + B
note that F(X) = Y
So, looking at the alternatives in the question, only Y = 7X/3 - 8 is equivalent to Y = AX + B, where:
A = 7/3
B = - 8
then
<em>a function of the 1st degree</em>
answer:
<h2>Y = (7/3)X - 8</h2>