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3 years ago

So this set

Mathematics

1 answer:

Citrus2011 [14]3 years ago

8 0

To figure out if the sets are equivalent first you need to combine like terms if possible. Hope this picture helps.

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A library wants to buy a new computer that cost $989.99. So far, the library has collected $311. 25 in donations. About how much

mel-nik [20]

Answer:

$678.74

Step-by-step explanation:

989.99-311.25 = 678.74

hoped this helped

5 0

2 years ago

crater Lake in Oregon in shaped like a circle with a diameter of about 5.5 miles. What is the area of the surface of crater lake

N76 [4]

Answer:

Given the statement: Crater Lake in Oregon in shaped like a circle with a diameter of about 5.5 miles.

Area of circle is given by:

$A = \pi \frac{d^2}{4}$

where

A represents the area of a circle

d represents the diameter of a circle.

then;

It is given that Surface of Crater lake is shaped like a circle.

Substitute the given values, we have;

Area of a circle = $\pi \frac{(5.5)^2}{4}$

= $3.14 \times \frac{30.25}{4} =3.14 \times 7.5625 = 23.74625$ square miles

therefore, the area of a surface of a crater lake is, 23.74625 square miles.

3 0

3 years ago

3. A piece of white oak has a densityof 0.77 g/cm and a mass of 100 g,what would be the volume of thesample? PLEASE HELP!

Nezavi [6.7K]

$\text{Volume}=129.87cm^3$

Explanation

Step 1

the density of an object is given by:

$\text{density}=\text{ }\frac{mass}{\text{volume}}$

Step 2

let

$\begin{gathered} \text{density}=0.77\frac{g}{cm^3} \\ \text{mass}=\text{ 100 g} \\ \end{gathered}$

Step 3

replace,

$\begin{gathered} \text{density}=\text{ }\frac{mass}{\text{volume}} \\ 0.77\frac{g}{cm^3}=\frac{100g}{\text{volume}} \\ \text{volume}\cdot0.77\frac{g}{cm^3}=\text{1}00\text{ g} \\ \\ \text{Volume}=\frac{100\text{ g}}{0.77\frac{g}{cm^3}} \\ \text{Volume}=129.87cm^3 \end{gathered}$

I hope this helps you

5 0

1 year ago

What would be the surface area of this?

victus00 [196]

I don’t see a picture so I can’t exactly answer this. Sorry

5 0

3 years ago

Joanne has a cylindrical, above ground pool. the depth (height) of the pool is 1/2 of its radius, and the volume is 1570 cubic f

diamong [38]

Answer:

314 ft²

Step-by-step explanation:

Data provided in the question:

Depth (height) of the pool = $\frac{1}{2}$ of its radius

let the radius be 'r' ft

thus,

Depth (height) of the pool, h = $\frac{r}{2}$ ft

Volume of the pool = 1570 ft³

also,

Volume of cylinder = πr²h

thus,

1570 ft³ = πr²h

1570 ft³ = $\pi r^2(\frac{r}{2})$

3140 = 3.14 × r³ [ π = 3.14 ]

r³ = 1000 ft³

r = 10 ft

Thus,

Area of the bottom surface = πr²

= 3.14 × 10²

= 314 ft²

5 0

3 years ago