Answer:
0.7486 = 74.86% observations would be less than 5.79
Step-by-step explanation:
I suppose there was a small typing mistake, so i am going to use the distribution as N (5.43,0.54)
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
The general format of the normal distribution is:
N(mean, standard deviation)
Which means that:

What proportion of observations would be less than 5.79?
This is the pvalue of Z when X = 5.79. So



has a pvalue of 0.7486
0.7486 = 74.86% observations would be less than 5.79
The base is 15 ft.
Using the formula A=bh, we substitute the information we have. We know the area and the height:
127.5 = b(8.5)
Divide both sides by 8.5:
127.5/8.5 = b(8.5)/8.5
15 = b
The base is 15.
Answer:
m = 2
Step-by-step explanation:
m m+3
----- = ----------
4 10
Using cross products
10m = 4(m+3)
Distribute
10m = 4m+12
Subtract 4m from each side
10m-4m = 4m-4m+12
6m = 12
Divide by 6
6m/6 = 12/6
m = 2