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3 years ago

Ray recorded the amount he paid for his phone bill each month for the year in this table.

Mathematics

2 answers:

Aleks [24]3 years ago

7 0

Answer:

sorry this is not the answer

Step-by-step explanation:

Wittaler [7]3 years ago

6 0

Select the correct answer from each drop-down menu. Ray recorded the amount he pald for his phone bill each month for the year in this table. $28 $ 27 $26 $25 $32 $ 26 $30 $25 $30 $28 $28 $30 The range of the data and the interquartile range is

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sweet [91]

Answer:

C. y = x + 3

Use, desmos.com

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3 years ago

Please help, I need input on if I did this correctly and you just substitute.

kow [346]

The value of h(t) when $t=\frac{15}{32}$ is 10.02.

Solution:

Given function $h(t)=-16t^2+15t+6.5$

To find the value of h(t) when $t=\frac{15}{32}$ :

$h(t)=-16t^2+15t+6.5$

Substitute $t=\frac{15}{32}$ in the given function.

$$h\left(\frac{15}{32} \right)=-16\left(\frac{15}{32} \right)^2+15\left(\frac{15}{32} \right)+6.5$

$$=-16\left(\frac{225}{1024} \right)+15\left(\frac{15}{32} \right)+6.5$

Now multiply the common terms into inside the bracket.

$$=-\left(\frac{3600}{1024} \right)+\left(\frac{225}{32} \right)+6.5$

Now, in the first term, the numerator and denominator both have common factor 16. So reduce the first term into the lowest term.

$$=-\left(\frac{225}{64} \right)+\left(\frac{225}{32} \right)+6.5$

To make the denominator same, take LCM of the denominators.

LCM of 64 and 32 = 64

$$=-\left(\frac{225}{64} \right)+\left(\frac{225\times2}{32\times2} \right)+6.5\times\frac{64}{64}$

$$=-\frac{225}{64} +\frac{450}{64}+\frac{416}{64}$

$$=\frac{-225+450+416}{64}$

$$=\frac{641}{64}$

= 10.02

$$h\left(\frac{15}{32} \right)=10.02$

Hence the value of h(t) when $t=\frac{15}{32}$ is 10.02.

8 0

3 years ago

If $12000 is invested in an account in which the interest earned is continuously compounded at a rate of 2.5%

vladimir1956 [14]

Complete Question

If $12000 is invested in an account in which the interest earned is continuously compounded at a rate of 2.5% for 3 years

Answer:

$ 12,934.61

Step-by-step explanation:

The formula for Compound Interest Compounded continuously is given as:

A = Pe^rt

A = Amount after t years

r = Interest rate = 2.5%

t = Time after t years = 3

P = Principal = Initial amount invested = $12,000

First, convert R percent to r a decimal

r = R/100

r = 2.5%/100

r = 0.025 per year,

Then, solve our equation for A

A = Pe^rt

A = 12,000 × e^(0.025 × 3)

A = $ 12,934.61

The total amount from compound interest on an original principal of $12,000.00 at a rate of 2.5% per year compounded continuously over 3 years is $ 12,934.61.

7 0

3 years ago

Need math help please!!

dem82 [27]

Answer:

my best guess is A

Step-by-step explanation:

5 0

3 years ago

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A number b increased by 3 is greater than or equal to -26

photoshop1234 [79]