First, set up an equation to model the problem. I will use the simple interest formula: I = (P)(r)(t); where P = principle amount, r = interest rate, and t = time.
First, substitute the known values into the formula:
P = $250
r = 0.3% = 0.003
t = 2
I = (250)(0.003)(2)
Now, all we have to do is simplify to find the amount of interest that will be added to Sydney's account after two years.
I = (0.75)(2)
I = 1.5
After two years, $1.50 will be added to Sydney's account. To find the total amount of money she will have after that time, just add the interest to her initial deposit:
250 + 1.5 = 251.50
So, your final answer is...
After two years, Sydney will have $251.50 in her account.
Hope this helps!
Answer:
LxWxH= 920
Step-by-step explanation:
hope this helps!
First, let's find the slope of the line using the slope formula, which is:
![m = \dfrac{y_2 - y_1}{x_2 - x_1}](https://tex.z-dn.net/?f=m%20%3D%20%5Cdfrac%7By_2%20-%20y_1%7D%7Bx_2%20-%20x_1%7D)
((
,
) and (
,
) are points on the line)
In context of this problem, we can use the formula to find the slope of the line between the two points:
![m = \dfrac{-2 -6}{7 - (-1)} = \dfrac{-8}{8} = -1](https://tex.z-dn.net/?f=m%20%3D%20%5Cdfrac%7B-2%20-6%7D%7B7%20-%20%28-1%29%7D%20%3D%20%5Cdfrac%7B-8%7D%7B8%7D%20%3D%20-1)
Now, we can use the slope in the point-slope formula, which will help us find the final equation of the line. (For reference, the point-slope formula is
where (
,
) is a point on the line)
In the context of the problem, we could use the formula to find the equation of the line:
![(y - 6) = -1(x + 1)](https://tex.z-dn.net/?f=%28y%20-%206%29%20%3D%20-1%28x%20%2B%201%29)
![(y - 6) = -x - 1](https://tex.z-dn.net/?f=%28y%20-%206%29%20%3D%20-x%20-%201)
![\boxed{y = -x + 5}](https://tex.z-dn.net/?f=%5Cboxed%7By%20%3D%20-x%20%2B%205%7D)
The equation of the line is y = -x + 5.
L don’t know to you need to (X)