Compounds that are gases at room temperature are covalent bonds (nonmetal + nonmetal).
Answer:
1. Atmosphere ⇒ Ocean ⇒ Marine Plants ⇒ Sediments ⇒ Natural Gas
.
2. Atmosphere ⇒ Land Plants ⇒ Natural Gas.
Explanation:
Hello,
In this case, it is widely known there are two ways in which natural gas is formed:
1. Atmosphere ⇒ Ocean ⇒ Marine Plants ⇒ Sediments ⇒ Natural Gas
.
In this one, the carbon dioxide in the atmosphere, is able to get through the ocean and in touch with marine plants which have the capacity to undergo photosynthesis and yield sugars which are subsequently fixated in the soil as sediments containing fossil fuels, coal and/or natural gas.
2. Atmosphere ⇒ Land Plants ⇒ Natural Gas.
In this one, the carbon dioxido also in the atmosphere is captured by the land plants which use it to undergo photosynthesis and subsequently fix it into the underground as fossil fuels, coal and/or natural gas as well.
Best regards.
<h3>
Answer:</h3>
18.02 g/mol
<h3>
General Formulas and Concepts:
</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
<h3>Explanation:
</h3>
<u>Step 1: Define</u>
Water H₂O
<u>Step 2: Find Formulas Mass</u>
<em>Formula mass is molar mass.</em>
Molar Mass of H - 1.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol
Answer:
0.51M
Explanation:
Given parameters:
Initial volume of NaBr = 340mL
Initial molarity = 1.5M
Final volume = 1000mL
Unknown:
Final molarity = ?
Solution;
This is a dilution problem whereas the concentration of a compound changes from one to another.
In this kind of problem, we must establish that the number of moles still remains the same.
number of moles initially before diluting = number of moles after dilution
Number of moles = Molarity x volume
Let us find the number of moles;
Number of moles = initial volume x initial molarity
Convert mL to dm³;
1000mL = 1dm³
340mL gives = 0.34dm³
Number of moles = initial volume x initial molarity = 0.34 x 1.5 = 0.51moles
Now to find the new molarity/concentration;
Final molarity = = = 0.51M
We can see a massive drop in molarity this is due to dilution of the initial concentration.
Answer:
The supersaturated solution
it is a solution usually very sugary
excess solute
the supersaturated solution is a solution
where there is solute and solvent, there is always interaction
Explanation:
The supersaturated solutions are solutions where the solute is in excess, the solute is in constant interaction with the solvent and being in excess it precipitates to the bottom of the solution.
A supersaturated solution has a very high osmolarity.