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Norma-Jean [14]
3 years ago
5

A child sits on a partially filled balloon and decreases the volume by half. What happens to the pressure inside of the balloon?

Chemistry
2 answers:
nordsb [41]3 years ago
3 0
The pressur in side increases alot because the air has gon down and the temp will increse
ella [17]3 years ago
3 0

Answer:

The pressure inside of the balloon increases by half

Explanation:

We can think of the balloon as a container of air ,which is a gas with a determinate volume and pressure.

According to <em>Boyle's law</em><em> </em>the volume of a gas is inversely proportional to its pressure.

P=\frac{1}{V}

For example, if a balloon volume is 3 liters  and the pressure inside the balloon 20 pascal and a man inflates the balloon up to 6 liters the pressure inside the balloon now is 10 pascal.

When a tank with 40 liters of nitrogen and 100 pascal of inner pressure is  compressed to 200 pascal of pressure, the volume goes down to 20 liters

So  when the volume increases the pressure decreases and vice versa

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4 years ago
What is the magnitude of the electrostatic force between a singly charged sodium ion and an adjacent singly charged chlorine ion
Arisa [49]
To know the electrostatic force between two charges or between two ions, you can use the Coulomb's Law. The equation is F = k*q1*q1/r^2, where F is the electrostatic force, q1 and q2 are the charger for Na and Cl, and r is the distance between the centers of both atoms. In literature, the distance is 0.5 nm or 0.5 x 10^-9 meters. The charge for Na+ and Cl- is the same magnitude but different in sign. Since Na+ is a cation, its charge is +1.603x10^-19 C (the charge of an electron). For Cl- being an anion, its charge is -1.603x10^-19 C. The constant k is an empirical value equal to 9x10^9. Using the formula:

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. A compound is composed of 2 atoms of Copper, 1 atom of Sulfur and 4 atoms of Oxygen. What
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<h3>Further explanation</h3>

Given

2 atoms of Copper, 1 atom of Sulfur and 4 atoms of Oxygen.

Required

The chemical formula

Solution

The number of atoms forming a compound is usually indicated from the subscript in the formula

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tekilochka [14]

Answer: The frequency of this light is 6.74\times 10^{17}Hz.

Explanation:-

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c = speed of light = 2.9\times 10^8m/s

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\nu=\frac{2.9\times 10^8m/s}{430\times 10^{-9}m}

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The frequency of this light is 6.74\times 10^{17}Hz.

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