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ICE Princess25 [194]
3 years ago
6

Write a method named isNumericPalindrome that accepts an integer parameter named num. If num is a palindrome the method must ret

urn true. Otherwise the method must return false. You can assume as a precondition that num has exactly 5 digits (i.e. it is between 10000 and 99999.) For example, 12321 is a palindrome while 12231 isn't because it's the same number if reversed. public boolean isNumericPalindrome(int num)
Computers and Technology
1 answer:
yaroslaw [1]3 years ago
4 0

Answer:

Explanation:

The following code is written in Java. It is a method that reverses the number that is passed as an argument and compares it to its original version. Then it finally returns the results of the comparison as a boolean (either True or False). Two test cases have been created and can be seen in the attached image below.

   public static boolean isNumericPalindrome(int num) {

       String numString = Integer.toString(num);

       String reversed = "";

       for (int i = numString.length()-1; i >= 0; i--) {

           reversed += numString.charAt(i);

       }

       return numString.equals(reversed);

   }

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Seven years after the famous Macworld 2007 keynote, the iPhone has seen significant enhancements in every area, but the original iPhone remains recognizable as Apple has maintained the overall look of a sleek design with a larger touchscreen and a single round home button on the face of the device.

Explanation:

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Trojan horse is the correct answer
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3 years ago
Write a program that grades arithmetic quizzes as follows: Ask the user how many questions are in the quiz. Ask the user to ente
kirill115 [55]

Answer:

The program in C++ is as follows:

#include <iostream>

using namespace std;

int main(){

   int questions, answer;

   cout<<"Questions: ";

   cin>>questions;

   int answerkey[questions];

   cout<<"Enter answer keys: ";

   for(int i = 0; i< questions; i++){

       cin>>answerkey[i];    }

   int correct = 0;

   cout<<"Enter answers: ";

   for(int i = 0; i< questions; i++){

       cin>>answer;

       if(answer == answerkey[i]){

           correct++;        }    }

   cout<<"Correct answers: "<<correct<<endl;

   cout<<"Percentage correct : "<<(100 * correct)/questions<<"%";

   return 0;

}

Explanation:

This declares the number of questions and the answers submitted to each equation

   int questions, answer;

Prompt to get the number of questions

   cout<<"Questions: ";

This gets input for the number of questions

   cin>>questions;

This declares the answerkey as an array

   int answerkey[questions];

Prompt to get the answer key

   cout<<"Enter answer keys: ";

This iteration gets the answer key for each question

<em>    for(int i = 0; i< questions; i++){</em>

<em>        cin>>answerkey[i];    }</em>

This initializes the number of correct answers to 0

   int correct = 0;

Prompt to get the enter the answers

   cout<<"Enter answers: ";

This iterates through the answer keys

   for(int i = 0; i< questions; i++){

This gets the answer to each question

       cin>>answer;

This compares the answer to the answer key of the question

       if(answer == answerkey[i]){

If they are the same, correct is incremented by 1

           correct++;        }    }

Print the number of correct answers

   cout<<"Correct answers: "<<correct<<endl;

Print the percentage of correct answers

   cout<<"Percentage correct : "<<(100 * correct)/questions<<"%";

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To learn more about context switch, click here,

brainly.com/question/21685677

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Answer:

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Explanation:

i had that question before

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