Write a method named isNumericPalindrome that accepts an integer parameter named num. If num is a palindrome the method must ret
1 answer:
Answer:
Explanation:
The following code is written in Java. It is a method that reverses the number that is passed as an argument and compares it to its original version. Then it finally returns the results of the comparison as a boolean (either True or False). Two test cases have been created and can be seen in the attached image below.
public static boolean isNumericPalindrome(int num) {
String numString = Integer.toString(num);
String reversed = "";
for (int i = numString.length()-1; i >= 0; i--) {
reversed += numString.charAt(i);
}
return numString.equals(reversed);
}
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Answer:
See the code below and the algorithm explanation on the figure.
Explanation:
The explanation in order to get the answer is given on the figure below.
Solving this problem with C. The program is given below:
#include <stdio.h>
int main(void) {
int n, Even=0, Odd=0, Zeros=0;
for (;;) {
printf("\nEnter the value the value that you want to check(remember just integers): ");
//IF we input a non-numeric character the code end;
if (scanf("%d", &n) != 1) break;
if (n == 0) {
Zeros++;
}
else {
if (n % 2) {
Even++;
}
else {
Odd++;
}
}
}
printf("for this case we have %d even, %d odd, and %d zero values.", Even, Odd, Zeros);
return 0;
}
