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Yuri [45]
3 years ago
7

If a car traveled 10miles and then continues for another 6 hours at a steady rate of 30miles per hour how many total miles wit i

t have traveled?
Mathematics
2 answers:
mixer [17]3 years ago
4 0

Answer: 2

Step-by-step explanation:

because e=mc

erica [24]3 years ago
3 0

Answer:

190

Step-by-step explanation:

30x6=180+10=190

Please consider marking as Brainliest. Thank You.

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The area of a square mural is 144x2 - 72x + 9. What is the length of one side<br> of the mural?
marissa [1.9K]

Answer:

-0.25 units

Step-by-step explanation:

144x^2 - 72x + 9 = 0

common factor: 9

16x^2 - 8x + 1 = 0

(4x + 1)^2 = 0

4x +1 = 0

4x = -1

x = -0.25 units

6 0
3 years ago
Help please!!!<br> How do i explain this! ????????????????!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
AURORKA [14]

Answer:

The answer should be 5 logx + 2 log y

8 0
3 years ago
7m+n over q= 2m. How do I solve for q
ryzh [129]
I believe you have to get all the like terms on the same side. So since 7m+n is being divided by Q in order to move it to the other side of the equal sign you must multiply each side by Q. Then you would end up with 7m+n=2m(q). 7m and 2m are alike so you then take the 2m and subtract it from each side. So your equation should look like 7m-2m+n=Q. Then combine your like terms and you end up with 5m+n=q 
7 0
3 years ago
In △QRS, QR ‖ TU. Given that TQ=6, ST=10, and UR=15, find SU.
tresset_1 [31]

Answer:

SU=25

Step-by-step explanation:

We can set up a ratio as STU and SQR are similar because of the SAS similarity theorem.

TQ:SQ

SQ=ST+TQ=10+6=16

6:16=3:8

Therefore the ratio of STU:SQR is 3:8

We can use this to find SU

UR:SR=3:8

15:SR=3:8

Cross multiply

3SR=120

SR=40

SU=SR-UR

SU=40-15

SU=25

8 0
3 years ago
When you have two side lengths of 2in and 4.5in What is the other side length?
nika2105 [10]

Answer:

The solution for the other side length is the interval

(2.5,6.5)

Step-by-step explanation:

I will assume that is a triangle

we know that

The <u><em>Triangle Inequality Theorem</em></u> states that the sum of any 2 sides of a triangle must be greater than the measure of the third side

Let

x ---> the measure of the third side

Applying the Triangle Inequality Theorem

1) 2+4.5 > x

6.5 > x

Rewrite

x < 6.5\ in

2) 2+x> 4.5

x> 2.5\ in

therefore

The solution for the other side length is the interval

(2.5,6.5)

5 0
4 years ago
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