3 years ago

HeLP me ASAP PLEASE ASAP i will give 50 points for the right answer

Mathematics

1 answer:

hammer [34]3 years ago

6 0

If you looked it up, then you will get the right answer. Just a tip. Your welcome

You might be interested in

How do I do this number 5 and 6

grin007 [14]

Answer:

5. 40

Step-by-step explanation:

(14) +(4x+6) = 8x

14 + 4x+ 6 = 8x

20 = 8x - 4x

4x = 20

x = 5

RT = 8x

= 8 * 5....since x = 5

= 40

4 0

2 years ago

Place parentheses in the following equation to make it true

Murrr4er [49]

Multiplexed or multiplied?

6 0

3 years ago

Read 2 more answers

Given that

Digiron [165]

Answer: 32 degrees

Step-by-step explanation:

8 0

2 years ago

Mrs. Grady surveyed 30 students, 12 of which said they liked basketball, 16 of which said they liked hockey, and 4 of which said

diamong [38]

Because 4 people likes both, we take out 4 from the sum of both the number to avoid double count.

People who like both sports = 12 + 16 - 4 = 24
People who do not like either sport = 30 - 24 = 6

4 0

4 years ago

Solve the given differential equation by using an appropriate substitution. The DE is a Bernoulli equation.

Mama L [17]

Multiplying both sides by $y^2$ gives

$xy^2\dfrac{\mathrm dy}{\mathrm dx}+y^3=1$

so that substituting $v=y^3$ and hence $\frac{\mathrm dv}{\mathrm dv}=3y^2\frac{\mathrm dy}{\mathrm dx}$ gives the linear ODE,

$\dfrac x3\dfrac{\mathrm dv}{\mathrm dx}+v=1$

Now multiply both sides by $3x^2$ to get

$x^3\dfrac{\mathrm dv}{\mathrm dx}+3x^2v=3x^2$

so that the left side condenses into the derivative of a product.

$\dfrac{\mathrm d}{\mathrm dx}[x^3v]=3x^2$

Integrate both sides, then solve for $v$ , then for $y$ :

$x^3v=\displaystyle\int3x^2\,\mathrm dx$

$x^3v=x^3+C$

$v=1+\dfrac C{x^3}$

$y^3=1+\dfrac C{x^3}$

$\boxed{y=\sqrt[3]{1+\dfrac C{x^3}}}$

6 0

3 years ago