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3 years ago

I need help on 1 pleased

Mathematics

1 answer:

MissTica3 years ago

5 0

772 pounds of food. 193 times 4

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Are 1 and 2 correct ? I need help

Rama09 [41]

1 is wrong there are two numbers greater than 4 but less than or equal to 6.
the first one was correct

5 0

3 years ago

3x-5(x-5)= -4+2x+1<br><br> Can someone help me out plzzzz

dusya [7]

Answer:

Step-by-step explanation:

So basically first distribute the -5 to the stuff in the parenthesis and then solve.

Hope I helped!! :)

7 0

3 years ago

Say that a supplier claims they are 99% confident that their products will be in the interval of 50.02 to 50.38. You take sample

nydimaria [60]

Answer:

The supplier becomes less accurate than they otherwise would have tried to claim. A further explanation is below.

Step-by-step explanation:

According to the provider, this same width of that same confidence interval would be as follows:

= $50.38 - 50.02$

= $0.36$

Depending on the input observed, the width including its confidence interval would be as follows:

= $50.39 - 50.01$

= $0.38$

As even the width of that interval again for survey asserted > the width including its confidence interval according to the provider's statement, we could conclude that such is the appropriate reaction.

3 0

3 years ago

Help help i need help anyone ?

REY [17]

-9-6i/-3-2i
Factor -3 out of expression
-3(3+2i)/-3-2i
Then extract the negative sign out of the expression
-3(3+2i)/-(3+2i)
Reduce the fraction with -(3+2i)
-3/-1
-3*-1=3
Hope this helps

3 0

3 years ago

Help center of circle

Lelu [443]

Answer:

Center = (7, - 5)

Radius = 3

Step-by-step explanation:

${x}^{2} + {y}^{2} + 14x - 10y + 65 = 0 \\ {x}^{2} + 14x + {y}^{2} - 10 + 65 = 0 \\ ( {x}^{2} + 14x + {7}^{2}) - {7}^{2} + ({y}^{2} - 10y + {5}^{2}) \\- {5}^{2} + 65 = 0 \\ (x + 7)^{2} + (y - 5)^{2} - 49 - 25 + 65 = 0 \\ (x + 7)^{2} + (y - 5)^{2} - 49 + 40= 0 \\ (x + 7)^{2} + (y - 5)^{2} - 9= 0 \\ (x + 7)^{2} + (y - 5)^{2} = 9 \\ (x + 7)^{2} + (y - 5)^{2} = {3}^{2} \\ equating \: it \: with \: \\ (x - h)^{2} + (y - k)^{2} = {r}^{2} \\ - h = 7 \implies \: h = - 7 \\ - k = - 5 \implies \: k = 5 \\ center = ( - h, \: - k) = (7, \: \: - 5) \\ \\ radius \: r = 3$

7 0

3 years ago