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tresset_1 [31]
3 years ago
7

The age at which a person can be tried as an adult

Mathematics
1 answer:
daser333 [38]3 years ago
5 0

Answer:

giyi

Step-by-step explanation:

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How to solve 0.225555555555 into a fraction mental math strategy​
Naddika [18.5K]

Answer:

Convert to a decimal by dividing the numerator by the denominator.

4.43349753 just easy

6 0
3 years ago
The Town of Hertfordshire clerk knows that 23% of dogs in the town have completed emotional support training. Hertfordshire plan
Nataly_w [17]

Answer:

95.64% probability that under 30% of the dogs are emotional support trained

Step-by-step explanation:

For each dog, there are only two possible outcomes. Either they have completed emotional support training, or they have not. So we use the binomial probability distribution to solve this problem.

However, we are working with samples that are considerably big. So i am going to aproximate this binomial distribution to the normal.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

\mu = E(X) = np = 100*0.23 = 23

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{100*0.23*0.77} = 4.21

What is the probability that under 30% of the dogs are emotional support trained?

30% of 100 is 0.3*100 = 30

So this is the pvalue of Z when X = 30.

Z = \frac{X - \mu}{\sigma}

Z = \frac{30 - 23}{4.1}

Z = 1.71

Z = 1.71 has a pvalue of 0.9564.

So there is a 95.64% probability that under 30% of the dogs are emotional support trained

5 0
3 years ago
Which of the following example is an improper fraction
Vsevolod [243]

Answer:

an example of an improper fraction is 57/4 or 21/6. cuz ur numerator is larger than ur denominator

5 0
3 years ago
Read 2 more answers
 (6,-3) and y = - 6x - 3
Hatshy [7]
Wait what's the question tho?
is it if this point is on the line?
cause it's not
-y=mx+b
3=-6(6)-3
-3=-36-3
-3 does not equal -39
hence, point is not on the line
3 0
3 years ago
Find the volume of the figure.<br> 2.25 m<br> 4<br> m<br> 2.5 m<br> no
liberstina [14]

<u>Given</u>:

Given that the figure is a triangular prism.

The length of the prism is 4 m.

The base of the triangle is 2.5 m.

The height of the triangle is 2.25 m.

We need to determine the volume of the triangular prism.

<u>Volume of the triangular prism:</u>

The volume of the triangular prism can be determined using the formula,

V=\frac{1}{2}bhl

where b is the base of the triangle,

h is the height of the triangle and

l is the length of the prism.

Substituting b = 2.5, h = 2.25 and l = 4 in the above formula, we get;

V=\frac{1}{2}(2.5)(2.25)(4)

V=\frac{1}{2}(22.5)

V=11.25 \ m^3

Thus, the volume of the triangular prism is 11.25 m³

4 0
3 years ago
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