Answer:
Step-by-step explanation:
![\displaystyle \sum_{n=1}^{20} (3n+2)=\dfrac{(62+5)*20}{2} =10*67=670\\](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Csum_%7Bn%3D1%7D%5E%7B20%7D%20%283n%2B2%29%3D%5Cdfrac%7B%2862%2B5%29%2A20%7D%7B2%7D%20%3D10%2A67%3D670%5C%5C)
This is false, because every positive and negative number is real.
Make sure your decimals line up for addition and subtraction.
73.4581
+ 2.0033
--------------------
75.4614
Rounding to the nearest thousandth
75.461
we rounded down because the ten thousandths place is a 4 so thousandths place stays as is. If it were 5 or more it would have rounded up to a 2.
The prime number on the number would be 3