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SVETLANKA909090 [29]
3 years ago
14

The slope of a line can be stated many ways if not put into simplest form.

Mathematics
1 answer:
algol133 years ago
5 0

Answer:

slope is -3 or, so false

Step-by-step explanation:

You might be interested in
How much fibre does the NHS recommend adults take in as a daily dose?
iVinArrow [24]

Answer:

The answer is D: 30 g.

Step-by-step explanation: I googled the answer to this question and it said that NHS reccomends that adults take around 30 g of fibre as a daily dose. If you take less, you may not get enough, but if you take more, you would possibly overdose. So, the answer is D: 30g.

8 0
3 years ago
Part A: The area of a square is (16x2 − 8x + 1) square units. Determine the length of each side of the square by factoring the a
d1i1m1o1n [39]

Answer:

see below

Step-by-step explanation:

16x^2 − 8x + 1

(4x)^2 -8x +1

Factor

This is a perfect square trinomial

a^2 -2ab +b^2 = (a-b)(a-b)

(4x)^2 -8x +1 = (4x-1) (4x-1)

The area of a square is given by

A = s^2

(4x-1) ^2 = s^2

4x-1 = s

The side length is 4x-1

(81x^2 − 4y^2)

(9x)^2 - (2y)^2

This is the difference of squares

a^2 - b^2 = (a-b) (a+b)

(9x-2) (9x+2)

The area of a rectangle is

A = l*w

(81x^2 − 4y^2)  = (9x-2) (9x+2)

The dimensions are (9x-2) (9x+2)

3 0
3 years ago
Given that e= 2i – 5j + 9k and f= 8i + 15j + k, find 3f – 2e.
ipn [44]

Plug in "8i + 15j + k" for "f", and "2i – 5j + 9k" for "e"

3(8i + 15j + k) - 2(2i – 5j + 9k)

Distribute 3 to (8i + 15j + k) & - 2 to (2i – 5j + 9k)

3(8i + 15j + k) = 24i + 45j + 3k

-2(2i - 5j + 9k) = -4i + 10j - 18k

-------------------------------------------------------------------------------------------------------------------

Simplify. Combine like terms

24i - 4i + 45j + 10j + 3k - 18k

(24i - 4i) + (45j + 10j) + (3k - 18k)

20i + 55j - 15k is your answer, or (C)

-------------------------------------------------------------------------------------------------------------------

hope this helps

5 0
3 years ago
Read 2 more answers
I NEED HELP ASAP IT IS DUE AT MIDNIGHT PLEASEEEEEE!!!!
IgorC [24]

Answer:

A = -2.2

B =  -1.7

C =  1.87

D =  19.97

Step-by-step explanation:

A = 7.4 - 9.6 = -2.2

B = -2.2 + 0.5 = -1.7

C = -1.1(-1.7) = 1.87

D = 18.1 + 1.87 = 19.97

3 0
3 years ago
Read 2 more answers
Consider the two data sets below:
alina1380 [7]

Answer:

<u><em>Option c) The data sets will have the same values of their interquartile range.</em></u>

<u><em></em></u>

Explanation:

<u>1. The values are in order: </u>they are in increasing oder, from lowest to highest value.

<u>2. Calculate the interquartile range.</u>

<em />

<em>Interquartile range</em>, IQR, is the third quartile, Q3, less the first quartile Q1:

  • IQR = Q3 - Q1

To find the first and the third quartile, first find the median:

<u>Data Set 1</u>: 19, 25, 35, 38, 41, 49, 50, 52, 59

             [19, 25, 35, 38],  41,  [49, 50, 52, 59]

                                         ↑

                                     median = 41

   

<u>Data Set 2</u>: 19, 25, 35, 38, 41, 49, 50, 52, 99

             [19, 25, 35, 38] , 41,  [49, 50, 52, 99]

                                         ↑

                                      median = 41

Now find the median of each subset: the values below the median and the values above the median.

Data set 1: <u>First quartile</u>

                [19, 25, 35, 38],

                            ↑

                           Q1 = [25 + 35] / 2 = 30

                   <u>Third quartile</u>

                   [49, 50, 52, 59]

                                ↑

                                Q3 = [50 + 52] / 2 = 51

                     IQR = Q3 - Q1 = 51 - 30 = 21

Data set 2: <u> First quartile</u>

                   [19, 25, 35, 38]

                               ↑

                               Q1 = [25 + 35] / 2= 30

                  <u>Third quartile</u>

                   [49, 50, 52, 99]

                                ↑

                                Q3 = [52 + 50]/2 = 51

                   IQR = 51 - 30 = 21

Thus, it is shown that the data sets have will have the same values for the interquartile range: IQR = 21. (option c)

This happens because replacing one extreme value (in this case the maximum value) by other extreme value does not affect the median.

<em>An outlier will change the range</em> because the range is the maximum value less the minimum value.

5 0
3 years ago
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