2 years ago

Lul JAJAJAJJAJAJKJSAHDKJHWAKJSHD

Mathematics

1 answer:

victus00 [196]2 years ago

3 0

Answer:

ksjajajajakkkakakaakakkajjjjjj

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Step-by-step explanation:

Given equation:

$x^2+(p-3)y^2-4x+6y-16=0$

<u>Standard equation of a circle:</u>

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If you expand this equation, you will see that the coefficient of $y^2$ is always one.

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<u>Additional information</u>

To rewrite the given equation in the standard form:

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