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Tju [1.3M]
3 years ago
13

The product of 1.3x10^-4 and a number n results in 2.6x10^12. What idle the value of n

Mathematics
2 answers:
Mademuasel [1]3 years ago
5 0
1.3 x 10^-4 * n = <span>2.6 x 10^12
n = </span>2.6 x 10^12 / 1.3 x 10^-4
n = (2.6 / 1.3) x 10^16
n = 2 x 10^16

Answer
Idle the value of n = 2 x 10^16
Degger [83]3 years ago
5 0
1.3 \times 10^{-4} \times n = 2.6 \times 10^{12}

n = \dfrac{2.6 \times 10^{12}}{1.3 \times 10^{-4}}

n = \dfrac{2.6}{1.3} \times \dfrac{10^{12}}{10^{-4}}

n = 2 \times 10^{12 - (-4)}

n = 2 \times 10^{12 + 4}

n = 2 \times 10^{16}

Answer: The value of n is 2 \times 10^{16}
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jasenka [17]

Answer:

The sum of all the external angles of a triangle is 360°.

Step-by-step explanation:

Let there are n sides in a polygon.

So, there are n internal angles in the polygon, let ∠i1, ∠i2, ∠i3, ..., ∠in are the measure of n internal angles of the polygon.

The measure of external angle corresponding to ∠i1,  ∠1= 180°-∠i1,

The measure of external angle corresponding to ∠i2, ∠2 = 180°-∠i2,

Similarly, the measure of external angle corresponding to ∠in, ∠n = 180°-∠in.

Now, the sum of all the external angles of the polygon,

(∠1+∠2+...+∠n)=(180°-∠i1)+(180°-∠i2)+...+(180°-∠in)

=(180°+180°+...n times)-(∠i1+∠i2+...+∠in)

=n x 180° - (∠i1+∠i2+...+∠in)

As ∠i1+∠i2+...+∠in is the sum of all the internal angles of the polygon.

So, the sum of all the external angles of the polygon =

(n x 180°) - (sum of all the internal angles of the polygon).

In the case of a triangle, n=3  and the sum of all the three internal angles, ∠i1+∠i2+∠i3 = 180°.

Therefore, the sum of all the external angles of a triangle,

∠1+∠2+∠3 =3x180°-(∠i1+∠i2+∠i3)

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Hence, the sum of all the external angles of a triangle is 360°.

5 0
3 years ago
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yKpoI14uk [10]

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3 years ago
12.
IrinaVladis [17]

Answer:

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Step-by-step explanation:

We have a rectangular room with dimensions:

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2*x  =  500 - 140

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x  =  180  ft

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Hi!

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C is <u>FALSE</u> - Explained above.

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