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3 years ago

Help me with this please!!!!

Mathematics

2 answers:

sveticcg [70]3 years ago

6 0

Answer:

yes

Step-by-step explanation:

it said it is a perpendicular BISECTOR, H is the mid point of KI, HK = 7

Klio2033 [76]3 years ago

3 0

$\huge{\underline{\underline{\boxed{\sf{\red{Answer࿐}}}}}}$

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The volume of clay used to build a cylindrical pillar with a height of 9 centimeters is 324 pi cubic centimeters. The area of th

Marta_Voda [28]

Answer:

36 (Fill 3 in the blank)

Step-by-step explanation:

Given:

Volume of a cylinder = 324 π

Height = 9 cm

The formula to find the volume of a cylinder = Base area * height.

Base is a circle. So the area of a circle = πr^2

Volume of the cylindrical pillar = πr^2 h

324 π = πr^2 . 9

πr^2 = 324 π /9

πr^2 = 36 π

The area of the base = 36 π

Thank you.

7 0

3 years ago

Read 2 more answers

Find the area (in square feet) of a rectangle that measures 17" × 3'10".

Kitty [74]

Answer:

65 feet and 2 inches

Step-by-step explanation:

to find the area of a rectangle you need to multiply length times width in this case 17" times 3'10". But first you must convert everything into the same form(in this case feet) so first you can convert everything to inches by multiplying 3 times 12 which gives you 36 then add the 10, so it is now 46 inches then multiply that by 17 and altogether it is 782 inches, then divide by 12 (to convert it back to feet) and the answer is 65.1666666667. After you can round and get 65 feet and 2 inches.

6 0

2 years ago

Solve equation 13=x/7+5

yuradex [85]

Answer:

Step-by-step explanation:

Isolate the variable (x). Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.

First, subtract 5 from both sides:

13 (-5) = (x/7) + 5 (-5)

13 - 5 = x/7

8 = x/7

Isolate the variable x. Multiply 7 to both sides:

8(7) = (x/7)(7)

8(7) = x

x = 8 * 7

x = 56

56 is your answer for x.

3 0

3 years ago

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Suppose the number of children in a household has a binomial distribution with parameters n=12n=12 and p=50p=50%. Find the proba

nadya68 [22]

Answer:

a) 20.95% probability of a household having 2 or 5 children.

b) 7.29% probability of a household having 3 or fewer children.

c) 19.37% probability of a household having 8 or more children.

d) 19.37% probability of a household having fewer than 5 children.

e) 92.71% probability of a household having more than 3 children.

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem, we have that:

$n = 12, p = 0.5$

(a) 2 or 5 children

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{12,2}.(0.5)^{2}.(0.5)^{10} = 0.0161$

$P(X = 5) = C_{12,5}.(0.5)^{5}.(0.5)^{7} = 0.1934$

$p = P(X = 2) + P(X = 5) = 0.0161 + 0.1934 = 0.2095$

20.95% probability of a household having 2 or 5 children.

(b) 3 or fewer children

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{12,0}.(0.5)^{0}.(0.5)^{12} = 0.0002$

$P(X = 1) = C_{12,1}.(0.5)^{1}.(0.5)^{11} = 0.0029$

$P(X = 2) = C_{12,2}.(0.5)^{2}.(0.5)^{10} = 0.0161$

$P(X = 3) = C_{12,3}.(0.5)^{3}.(0.5)^{9} = 0.0537$

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0002 + 0.0029 + 0.0161 + 0.0537 = 0.0729$

7.29% probability of a household having 3 or fewer children.

(c) 8 or more children

$P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 8) = C_{12,8}.(0.5)^{8}.(0.5)^{4} = 0.1208$

$P(X = 9) = C_{12,9}.(0.5)^{9}.(0.5)^{3} = 0.0537$

$P(X = 10) = C_{12,10}.(0.5)^{10}.(0.5)^{2} = 0.0161$

$P(X = 11) = C_{12,11}.(0.5)^{11}.(0.5)^{1} = 0.0029$

$P(X = 12) = C_{12,12}.(0.5)^{12}.(0.5)^{0} = 0.0002$

$P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) = 0.1208 + 0.0537 + 0.0161 + 0.0029 + 0.0002 = 0.1937$

19.37% probability of a household having 8 or more children.

(d) fewer than 5 children

$P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{12,0}.(0.5)^{0}.(0.5)^{12} = 0.0002$

$P(X = 1) = C_{12,1}.(0.5)^{1}.(0.5)^{11} = 0.0029$

$P(X = 2) = C_{12,2}.(0.5)^{2}.(0.5)^{10} = 0.0161$

$P(X = 3) = C_{12,3}.(0.5)^{3}.(0.5)^{9} = 0.0537$

$P(X = 4) = C_{12,4}.(0.5)^{4}.(0.5)^{8} = 0.1208$

$P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0002 + 0.0029 + 0.0161 + 0.0537 + 0.1208 = 0.1937$

19.37% probability of a household having fewer than 5 children.

(e) more than 3 children

Either a household has 3 or fewer children, or it has more than 3. The sum of these probabilities is 100%.

From b)

7.29% probability of a household having 3 or fewer children.

p + 7.29 = 100

p = 92.71

92.71% probability of a household having more than 3 children.

5 0

3 years ago

What is 3(exponent 2) multiplied by 3(exponent 3) ????

rusak2 [61]

$\huge\boxed{243}$

___________________________________________________________

$\boxed{Explanation}$

So, we have the following equation...

$3^2*3^3=(?)$

Remember $3^2$ and $3^3$ is the following...

$3^2=3*3\\3^3=3*3*3$

Therefore, $3*3=9\\3*3*3=27\\9*27=243$

So, your final answer is $\boxed{243}$ .

___________________________________________________________

$\huge\boxed{Thanks,\;Plip.}$

3 0

3 years ago

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