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ohaa [14]
3 years ago
9

Its math and its on a number chart

Mathematics
1 answer:
Mrac [35]3 years ago
4 0

Answer:

It's English and it's in a book

Step-by-step explanation:

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Please help me with this problem
inn [45]

Answer:  Option 1

<u>Step-by-step explanation:</u>

\begin {array}{l|c|c||l}&\underline{\quad Length\quad}&\underline{\quad Width\quad}&\underline{\qquad Area\qquad}\\ Current&3x&x&3x\cdot x=3x^2\\Option\ 1\ (triple)&3(3x)=9x&3(x)=3x&9x\cdot 3x=27x^2\\Option\ 2\ (3\ closets)&3x&x&3(3x\cdot x)=9x^2\\\end{array}

Option 1 has a greater area than option 2.

4 0
3 years ago
Read 2 more answers
Solve for n.<br> 7 + 2n<br> ||<br> =<br> submit
Lunna [17]

Answer:

2

Step-by-step explanation:

7+2n = 11

2n = 11-7

2n = 4

n = 4/2

therefore n = 2

8 0
2 years ago
Evaluate: 2|x-4|+6 for x=2
Lina20 [59]
<h3>Answer:</h3>

10

<h3>Step-by-step explanation:</h3>

2|x -4| +6 \text{ for } x = 2 \\ 2|2 -4| +6 \\ 2|-2| +6 \\ 2(2) +6 \\ 4 +6 \\ 10

6 0
3 years ago
A cup of coffee at 93 degrees Celsius is placed in a room at 23 degrees Celsius. Suppose that the coffee cools at a rate of 1 de
Alinara [238K]

Answer:

Step-by-step explanation:

The rate of change of temperature of the coffee with respect to time is expressed by the differential equation

dT/dt=k(T−A) when k = -1 and A = 23. The equation will become:

dT/dt = -(T-23)

If the coffee cools at the rate of 1°C per minute, then dT/dt = -1 and T = 70

Substituting into the equation:

-1 = k(70-23)

-1 = 47k

k = -1/47

k = -0.0213

Substituting k = -0.0213 into the original equation, the differential equation will be:

dT/dt=k(T−A)

dT/dt = -0.0213(T-23)

dT/dt = -0.0213T+0.489

To get the value of T, we will use variable separable method

dt = dT/-0.0213T+0.489

Integrate both sides

t = -0.0213ln(-0.0213T+0.489)

At t = 1 minute

1 = -0.0213ln(-0.0213T+0.489)

1/-0.0213 = ln(-0.0213T+0.489)

-46.95 = ln(-0.0213T+0.489)

Apply exp to both sides

e^-46.95 = e^ln(-0.0213T+0.489)

4.073×10^-21= -0.0213T+0.489

-0.0213T = 4.073×10^-21-0.489

-0.0213T = -0.489

T = 0.489/0.0213

T = 22.96°C

5 0
3 years ago
What are the solutions to. x^2 - x - 20 = 0
nignag [31]

Step-by-step explanation:

<em>x² - x - 20 = 0</em>

<em>x²</em><em> </em><em>-</em><em> </em><em>(</em><em>5</em><em>-</em><em>4</em><em>)</em><em> </em><em>x </em><em>-</em><em> </em><em>2</em><em>0</em><em> </em><em>=</em><em> </em><em>0</em><em> </em>

<em>x²</em><em> </em><em>-</em><em> </em><em>5x </em><em>+</em><em> </em><em>4x </em><em>-</em><em>2</em><em>0</em><em> </em><em>=</em><em> </em><em>0</em>

<em>x </em><em>(</em><em> </em><em>x </em><em>-</em><em> </em><em>5</em><em>)</em><em> </em><em>+</em><em> </em><em>4</em><em> </em><em>(</em><em> </em><em>x </em><em>-</em><em> </em><em>5</em><em>)</em><em> </em><em>=</em><em> </em><em>0</em>

<em>(</em><em>x </em><em>-</em><em> </em><em>5</em><em>)</em><em> </em><em>(</em><em>x+</em><em> </em><em>4)</em><em> </em><em>=</em><em> </em><em>0</em>

<em>Either</em><em>. </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em>

<em>x </em><em>-</em><em> </em><em>5</em><em> </em><em>=</em><em> </em><em>0</em>

<em>x </em><em>=</em><em> </em><em>5</em>

<em>Or, </em>

<em>x </em><em>+</em><em> </em><em>4</em><em> </em><em>=</em><em> </em><em>0</em><em> </em>

<em>x </em><em>=</em><em> </em><em>-</em><em>4</em>

3 0
3 years ago
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