If you were to roll two dice, how many different ways could you roll double fours?
1 answer:
You might be interested in
Answer:
- 3*2=
Step-by-step explanation:
<u>Given</u><u> </u><u>that</u><u>,</u><u> </u>
x*y=
3*2=
<u>Therefore</u><u>:</u><u>-</u>
Answer:
The number of people who paid $ 12 for reserved seat is 5,000
The number of people who paid $ 4 for general seat is 29,000
Step-by-step explanation:
Given as :
The total number of people attending a ballgame = 34,000
The total receipt of the ticket's seat = $ 176,000
The amount pad for reserved seat = $ 12
The amount paid for general admission = $ 4
Let The number of people for reserved seat = r
And The number of people for general admission = g
Now, According to question
The total number of people attending a ballgame = The number of people for reserved seat + The number of people for general admission
or, r + g = 34,000 ...........1
The total receipt of the ticket's seat = The amount pad for reserved seat × The number of people for reserved seat + The amount paid for general admission × The number of people for general admission
Or, $ 12 × r + $ ×4 g = $ 176,000 .........2
or, $ 12 × ( r + g ) = $ 12 × 34000
Or, $ 12 r + $ 12 g = $ 408,000
Solving equation
( $ 12 r + $ 12 g ) - ($ 12 r + $ 4 g ) = $ 408,000 - $ 176,000
Or, ( $ 12 r - $ 12 r ) + ( $ 12 g - $ 4 g ) = $ 232,000
Or 0 + 8 g = 232,000
∴ g =
I.e g = 29,000
So , The number of people for general admission = g = 29,000
Put the value of g in Eq 1
I.e r + g = 34,000
or , r = 34,000 - g
∴ r = 34000 - 29000
I.e r = 5,000
So, The number of people for reserved seat = r = 5,000
Hence The number of people who paid $ 12 for reserved seat is 5,000
And The number of people who paid $ 4 for general seat is 29,000 Answer