The radius is 10.4 cm. And the angle is 120 which is 1/3 of the circle.
Just use the area formula: 3.14 *r^2 to find the total area of 339.62 and then divide this by 3 to get 113.21. Then to subtract the triangle..find the area of the traingle which is 1/2 (10.4)^2 = 54.08. 113.21 - 54.08 = 59.13 which should be your answer
17) f(x) = 16/(13-x).
In order to find domain, we need to set denominator expression equal to 0 and solve for x.
And that would be excluded value of domain.
13-x =0
Adding x on both sides, we get
13-x +x = x.
13=x.
Therefore, domain is All real numbers except 13.
18).f(x) = (x-4)(x+9)/(x^2-1).
In order to find the vertical asymptote, set denominator equal to 0 and solve for x.
x^2 -1 = 0
x^2 -1^2 = 0.
Factoring out
(x-1)(x+1) =0.
x-1=0 and x+1 =0.
x=1 and x=-1.
Therefore, Vertical asymptote would be
x=1 and x=-1
19) f(x) = (7x^2-3x-9)/(2x^2-4x+5)
We have degrees of numberator and denominator are same.
Therefore, Horizontal asymptote is the fraction of leading coefficents.
That is 7/2.
20) f(x)=(x^2+3x-2)/(x-2).
The degree of numerator is 2 and degree of denominator is 1.
2>1.
Degree of numerator > degree of denominator .
Therefore, there would no any Horizontal asymptote.
Answer:
Y >= ABS(x-5) + 1
Step-by-step explanation:
Any graph that forms a "V" involves absolute value. So what equation would give the vertex y=1 at x=5, ABS(X-5) + 1.
Answer: 7/3
Step-by-step explanation:
R-P= (3,-7). the displacement vector.
P+x(R-P) moves to x times distance between
P+(R-P) = R moves to 100% of the distance.
Q = P+2/3(R-P)
= (-2,7)+2/3(3,-7)
= (-2,7)+(2,-14/3)
= (0,7-14/3)
= (0,7/3)
= (0,2.3333...)
Answer:
Range - {-4,0,12,20}
Step-by-step explanation:
Given that,
The function is :
g(x) = 4x –12
The domain of the function is {2, 3, 6, 8}.
g(2) = 4(2) –12 = -4
g(3) = 4(3) –12 = 0
g(6) = 4(6) –12 = 12
g(8) = 4(8) –12 = 20
Hence, the range of the function is {-4,0,12,20}.
