Answer: A. There all 90 degrees
Step-by-step explanation:
Given: Three parallel lines are cut by a transversal and one angle is measured to be 90 degrees.
We know that if two lines cut by transversal the following pairs are equal:
- Vertically opposite angles.
- Corresponding angles.
- Alternate interior angles.
- Alternate exterior angles.
If one angles measures 90°, then its supplement would be 90°.
Then by using above properties , we will get measure of all angles as 90°.
The maximum value can be determined by taking the derivative of the function.
(dh/dt) [h(t)] = h'(x) = -9.8t + 6
Set h'(x) = 0 to find the critical point
-9.8t + 6 = 0
-9.8t = -6
t = 6/9.8
Plug the time back into the function to find the height.
h(6/9.8) = -4.9(6/9.8)^2 + 6(6/9.8) + .6
= 2.4
And I don't understand your second question.
Answer:
Area = 168m^2
Step-by-step explanation:
Area of triangle = 1/2×base×height
Area = 1/2bh
= 1/2(8+16)(14)
= 168m^2
Answer:
d
Step-by-step explanation:
Using the Cosine rule to find ∠ A
cosA = 
= 
= 
=
, then
∠ A =
(
) ≈ 84.9° ( to 1 dec. place )
Answer:
the last one
Step-by-step explanation: