X(30;0)
y(0;50)
substitue 0 for y and solve for x
substitute 0 in for x and solve for y
Answer:
The width of a rectangle is: w = x+3
Step-by-step explanation:
Given
The length of rectangle = l = 4x
The area of rectangle = A = 4x² + 12x
To determine
The width of rectangle = w = ?
We know that the formula of the area of the rectangle is
substitute A = 4x² + 12x and l = 4x in the equation to determine the width w of the rectangle
4x² + 12x = w×4x
w = [4x² + 12x] / [4x]
Factor 4x² + 12x: 4x(x+3)
w = [ 4x(x+3) ] / [4x]
w = x+3
Therefore, the width of a rectangle is: w = x+3
Answer:
C. $11.20.
Step-by-step explanation: Just times the minutes by the $0.77 cents then plus the $5.81 to the answer getting your final answer.
Answer:
Find the stated lengths and values of rectangle M 26 N
LMNO. Round to the nearest tenth. P 5a - 7 2a + 8 240 9. MO
10. LP O 11. LM 12. ZNMO Find the missing leng..
Yes because 0 and 4 dont equal 10 and 20 and 40 dont equal 100. So no and 40 + 23 = 63.