Let width of the rectangular plot be x meters
then total of widths = 2x
and the length would be (550 - 2x) meters.
so the area = x(550 - 2x) = 550x - 2x^2
to find the maximum are find the derivative and equate to zero:-
f'(x) = 550 - 4x = 0
x = 550/4 = 137.5 meters = width
length = 550 - 2(137.5) = 275
Maximum area is when width = 137.5m and length = 275m
Answer: the maximum is 25.
Step-by-step explanation: a max/min can occur on the endpoints of a function and critical points of the function's derivative.
f(x)=x^4-x^2+13
f'(x)=4x^3-2x
The critical points of f'(x) occur when f'(x) is zero or undefined. f'(x) is not ever undefined in this case, so we just need to find the x values for when it's zero.
0=4x^3-2x
x=.707, -.707
Now that we have the critical points of f'(x) (.707 and -.707) and endpoints (-1 and 2), we can plug in these x values into the original function to determine its maximum. When you do this you'll find that the greatest y value produced occurs when x=2 and results in a max of 25.
Answer:
Its A
Step-by-step explanation:
Opposite of the opposite of two thirds IS TWO THIRDS!!!
Answer:
Yes it is because it is a straight line.
(I hope it helps, because i'm just learning about this meself so...)
A) The largest amount of kits the nurse can make is 75.
B) There would be 1 bandages and 1 lozenges in each kit.
