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joja [24]
3 years ago
14

I need to do the work of each one! help

Mathematics
1 answer:
iVinArrow [24]3 years ago
7 0
A. 3/4 • 7/8 = 21/32 < 7/8

B. 1 1/3 • 9/10 = 2 1/5 > 9/10

C. 3/4 • 7/8 = 21/32 < 7/8

D. 7/8 • 9/10 = 17/20 < 9/10

A is the correct answer.
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The least common multiple of two numbers is 3780, and the greatest common divisor is 18. given that one of the numbers is 180, w
garri49 [273]
<span>To solve these GCF and LCM problems, factor the numbers you're working with into primes: 
3780 = 2*2*3*3*3*5*7
180 = 2*2*3*3*5 
</span><span>We know that the LCM of the two numbers, call them A and B, = 3780 and that A = 180. The greatest common factor of 180 and B = 18 so B has factors 2*3*3 in common with 180 but no other factors in common with 180. So, B has no more 2's and no 5's
</span><span>Now, LCM(180,B) = 3780. So, A or B must have each of the factors of 3780. B needs another factor of 3 and a factor of 7 since LCM(A,B) needs for either A or B to have a factor of 2*2, which A has, and a factor of 3*3*3, which B will have with another factor of 3, and a factor of 7, which B will have. 
So, B = 2*3*3*3*7 = 378.</span>
8 0
3 years ago
Is 3x = 2y a linear equation?​
mel-nik [20]

Answer:

yes

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Which equation represents the circle described? (in picture)
Sedaia [141]
You are right. In circle equation we have =r² so the correct answer will be C od D.  But we have to calculate the center of a circle.

x^2+y^2-8x-6y+24=0\quad|-24\\\\(x^2-8x)+(y^2-6y)=-24

Complete the square:

x^2-8x+a^2\implies a=\dfrac{8x}{2x}=4\implies x^2-8x+4^2\\\\\\y^2-6y+b^2\implies b=\dfrac{6y}{2y}=3\implies y^2-6y+3^2

And we have:

(x^2-8x)+(y^2-6y)=-24\\\\(x^2-8x+4^2)-4^2+(y^2-6y+3^2)-3^2=-24\\\\&#10;(x-4)^2+(y-3)^2-16-9=-24\\\\(x-4)^2+(y-3)^2-25=-24\quad|+25\\\\\boxed{(x-4)^2+(y-3)^2=1}

So the answer is C (the same left side of equation).
6 0
3 years ago
Find the solution to each equation mentally or use your calculator. (do the opposite of the number on the left side of the equat
Alik [6]
A) a=10

B) b= -300

C) c= -1

D) -3567
7 0
3 years ago
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If AD is an altitude of triangle ABC, then angle ABC is:
alexira [117]
<ADB = 90 degrees

hope it helps
7 0
3 years ago
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