Answer:
To loop through a set of code a specified number of times, we can use the range() function, The range() function returns a sequence of numbers, starting from 0 by default, and increments by 1 (by default), and ends at a specified number.
Explanation:
hope this helps
The <u>camera, projector</u>, invented by the Lumiere brothers in Paris included a <u>phonograph</u>.
- camera, projector, phonograph
<u>Explanation:</u>
Lumiere brothers, French designers and pioneer producers of photographic gear who formulated the early movie camera and projector called the Cinématographe. A cinematograph is a movie film camera, which likewise fills in as a film projector and printer.
The key development at the core of the Cinématographe was the instrument through which film was moved through the camera. It shows moving pictures on a screen. Which goes rapidly enough, an image replaces another too rapidly for the eye to see the change, along these lines shaping a moving picture.
Answer:
cout << setprecision(2)<< fixed << number;
Explanation:
The above statement returns 12.35 as output
Though, the statement can be split to multiple statements; but the question requires the use of a cout statement.
The statement starts by setting precision to 2 using setprecision(2)
This is immediately followed by the fixed manipulator;
The essence of the fixed manipulator is to ensure that the number returns 2 digits after the decimal point;
Using only setprecision(2) in the cout statement will on return the 2 digits (12) before the decimal point.
The fixed manipulator is then followed by the variable to be printed.
See code snippet below
<em>#include <iostream> </em>
<em>#include <iomanip>
</em>
<em>using namespace std; </em>
<em>int main() </em>
<em>{ </em>
<em> // Initializing the double value</em>
<em> double number = 12.3456; </em>
<em> //Print result</em>
<em> cout << setprecision(2)<< fixed << number; </em>
<em> return 0; </em>
<em>} </em>
<em />
Answer:
See my explanations and attachment
Explanation:
Construct an 8k X 32 ROM using 2k X 8 ROM chips and any additional required components. Show how the address and data lines of the constructed 8k X 32 ROM are connected to the 2k X 8 chips.
I tried to solve it but I am not sure if I got the correct answer. Could anyone check my drawing and correct me?
