Answer:
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Step-by-step explanation:
Answer:
19
Step-by-step explanation:
im smart
Answer:
s = 22.5 m
Step-by-step explanation:
the equation for the speed change of a coach moving along a straight section of the road and starting braking at a speed of 20 m / s has the form v (t) = 25-5t. Using integral calculus, determine the coach's braking distance.
v (t) = 25 - 5 t
at t = 0 , v = 20 m/s
Let the distance is s.

Let at t = t, the v = 20
So,
20 = 25 - 5 t
t = 1 s
So, s = 25 x 1 - 2.5 x 1 = 22.5 m
Answer:
Step-by-step explanation:
The equation of a straight line can be represented in the slope-intercept form, y = mx + c
Where c = intercept
For two lines to be perpendicular, the slope of one line is the negative reciprocal of the other line. The equation of the given line is
y = 2x - 2
Comparing with the slope intercept form,
Slope, m = 2
This means that the slope of the line that is perpendicular to it is -1/2
The given points are (-3, 5)
To determine c,
We will substitute m = -1/2, y = 5 and x = - 3 into the equation, y = mx + c
It becomes
5 = -1/2 × - 3 + c
5 = - 3/2 + c
c = 5 + 3/2
c = 13/2
The equation becomes
y = -x/2 + 13/2