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Sonja [21]
3 years ago
14

Two joggers run 8 miles north and 5 miles west . what is the shortest distance, to the nearest tenth of a mile, they must travel

to return to their starting point ?
Mathematics
1 answer:
kobusy [5.1K]3 years ago
6 0

Answer:9.4 miles

Hope this helps

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Write (y^2)^3 without exponents, and fill in the blank​
irinina [24]

Answer:

y*y*y*y*y*y

Step-by-step explanation:

(y^{2})^{3} = y^{6} = y*y*y*y*y*y

7 0
3 years ago
What fraction is equal to 6​
faust18 [17]

Answer:

6/1

Step-by-step explanation:

4 0
3 years ago
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Where is the point at (2.5, -2.5) located
Vanyuwa [196]

Step-by-step explanation:

Go 2.5 units to the right from the origin (0,0) for your x coordinate

Go 2.5 units down from the origin (0,0) for your y coordinate

Where the lines meet is your point.

7 0
3 years ago
Use the Chain Rule to find the indicated partial derivatives. z = x^4 + xy^3, x = uv^4 + w^3, y = u + ve^w Find : ∂z/∂u , ∂z/∂v
k0ka [10]

I'll use subscript notation for brevity, i.e. \frac{\partial f}{\partial x}=f_x.

By the chain rule,

z_u=z_xx_u+z_yy_u

z_v=z_xx_v+z_yy_v

z_w=z_xx_w+z_yy_w

We have

z=x^4+xy^3\implies\begin{cases}z_x=4x^3+y^3\\z_y=3xy^2\end{cases}

and

\begin{cases}x=uv^4+w^3\\y=u+ve^w\end{cases}\implies\begin{cases}x_u=v^4\\x_v=4uv^3\\x_w=3w^2\\y_u=1\\y_v=e^w\\y_w=ve^w\end{cases}

When u=1,v=1,w=0, we have

\begin{cases}x(1,1,0)=1\\y(1,1,0)=2\end{cases}\implies\begin{cases}z_x(1,2)=12\\z_y(1,2)=12\end{cases}

and the partial derivatives take on values of

\begin{cases}x_u(1,1,0)=1\\x_v(1,1,0)=4\\x_w(1,1,0)=0\\y_u(1,1,0)=1\\y_v(1,1,0)=1\\y_w(1,1,0)=1\end{cases}

So we end up with

\boxed{\begin{cases}z_u(1,1,0)=24\\z_v(1,1,0)=60\\z_w(1,1,0)=12\end{cases}}

3 0
3 years ago
What is 70/6 as a mixed number
bija089 [108]
70/6 is basically saying "divide 70 by 6". So to get to a mixed numer, thats what you have to do.

70/6=11.666666...
(.666666..... is 2/3 as a fraction)

The answer is 11 2/3.


hope i helped!! :))
6 0
3 years ago
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